Answer:
Inductive reactance is 125.7 Ω
Explanation:
It is given that,
Inductance, ![L=50\ mH=0.05\ H](https://tex.z-dn.net/?f=L%3D50%5C%20mH%3D0.05%5C%20H)
Voltage source, V = 15 volt
Frequency, f = 400 Hz
The inductive reactance of the circuit is equivalent to the impedance. It opposes the flow of electric current throughout the circuit. It is given by :
![X_L=2\pi fL](https://tex.z-dn.net/?f=X_L%3D2%5Cpi%20fL)
![X_L=2\pi \times 400\ Hz\times 0.05\ H](https://tex.z-dn.net/?f=X_L%3D2%5Cpi%20%5Ctimes%20400%5C%20Hz%5Ctimes%200.05%5C%20H)
![X_L=125.66\ \Omega](https://tex.z-dn.net/?f=X_L%3D125.66%5C%20%5COmega)
![X_L=125.7\ \Omega](https://tex.z-dn.net/?f=X_L%3D125.7%5C%20%5COmega)
So, the inductive reactance is 125.7 Ω. Hence, this is the required solution.
Answer:
Vr = 20 [km/h]
Explanation:
In order to solve this problem, we have to add the relative velocities. We must remember that velocity is a vector, therefore it has magnitude and direction. We will take the sea as the reference measurement level.
Let's take the direction of the ship as positive. Therefore the boy moves in the opposite direction (Negative) to the reference level (the sea).
![V_{r}=30-10\\V_{r}=20 [km/h]](https://tex.z-dn.net/?f=V_%7Br%7D%3D30-10%5C%5CV_%7Br%7D%3D20%20%5Bkm%2Fh%5D)
Answer:
An object responds to a force by tending to move in the direction of that force
Explanation:
The inertia of a body can be defined with the help of Newton's second law
F = m a
Where F is the applied force, a is the acceleration of the body and m is the mass
the force and the acceleration are vectors that point in the same direction and m is a scalar constant that relates the two vectors, this scalar constant is called masses and it measures the resistance of the bodies to the change of motion.
From the previous statement we see that the statement that best describes inertia is:
An object responds to force by tending to move in the direction of the force.
W = 1/2k*x^2.
k = spring constant = 2500 n/m.
x = distance = 4 cm = 0.04m (convert to same units).
W = 1/2(2500)(0.04)^2 = 2J.
Answer:
The magnitude of the horizontal net force is 13244 N.
Explanation:
Given that,
Mass of car = 1400 kg
Speed = 17.7 m/s
Distance = 33.1 m
We need to calculate the acceleration
Using equation of motion
![v^2-u^2=2as](https://tex.z-dn.net/?f=v%5E2-u%5E2%3D2as)
Where, u = initial velocity
v = final velocity
s = distance
Put the value in the equation
![0-(17.7)^2=2a\times 33.1](https://tex.z-dn.net/?f=0-%2817.7%29%5E2%3D2a%5Ctimes%2033.1)
![a=\dfrac{-(17.7)^2}{33.1}](https://tex.z-dn.net/?f=a%3D%5Cdfrac%7B-%2817.7%29%5E2%7D%7B33.1%7D)
![a=-9.46\ m/s^2](https://tex.z-dn.net/?f=a%3D-9.46%5C%20m%2Fs%5E2)
Negative sign shows the deceleration.
We need to calculate the net force
Using newton's formula
![F = ma](https://tex.z-dn.net/?f=F%20%3D%20ma)
![F =1400\times(-9.46)](https://tex.z-dn.net/?f=F%20%3D1400%5Ctimes%28-9.46%29)
![F=-13244\ N](https://tex.z-dn.net/?f=F%3D-13244%5C%20N)
Negative sign shows the force is opposite the direction of the motion.
The magnitude of the force is
![|F| =13244\ N](https://tex.z-dn.net/?f=%7CF%7C%20%3D13244%5C%20N)
Hence, The magnitude of the horizontal net force is 13244 N.