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pogonyaev
3 years ago
12

While developing his periodic table, Dmitri Mendeleev broke his own rule and placed the element tellurium before iodine in the g

roup. He did this even though tellurium's atomic mass was known to be greater than iodine's. In his notes, Mendeleev stated that he expected tellurium to have a lower atomic mass than iodine. However, all measurements continue to show that tellurium has a greater atomic mass than iodine even though tellurium acts like it has a lower atomic mass. What is the most likely reason that Mendeleev placed tellurium before iodine?
Physics
2 answers:
icang [17]3 years ago
8 0
The most likely reason that Mendeleev placed tellurium before iodine is <span>Mendeleev observed that tellurium has chemical properties like other elements in its group, and he did not know that neutrons cause the greater atomic mass.</span>
mixer [17]3 years ago
4 0

Answer: he used chemical properties instead of atomic mass

Explanation:

Tellurium was placed that way because it's chemical properties. Tellurium was better fit in the category as oxygen and sulphur

The same ways iodine was placed in the same category of fluorine chlorine

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Which value is equivalent to 7.2 kilograms? A. 720 grams B. 7,200 grams C. 72,000 grams D. 720 milligrams E. 7,200 milligrams
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1 kilogram = 1,000 grams
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3 years ago
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A car’s tire rotates 5.25 times in 3 seconds. What is the tangential velocity of the tire?
Lena [83]

The tangential velocity of the car's tire is the product of the angular velocity and radius of the car's tire which is 11(r) m/s.

<h3>Angular velocity of the tire</h3>

The angular velocity of the tire is the rate of change of angular displacement of the tire with time.

The magnitude of the angular velocity of the tire is calculated as follows;

ω = 2πN

where;

  • N is the number of revolutions per second

ω = 2π x (5.25 / 3)

ω =  11 rad/s

<h3>Tangential velocity of the tire</h3>

The tangential velocity of the car's tire is the product of the angular velocity and radius of the car's tire.

The magnitude of the tangential velocity is caculated as follows;

v = ωr

where;

  • r is the radius of the car's tire

v = 11r m/s

Learn more about tangential velocity here: brainly.com/question/25780931

4 0
3 years ago
Science is hard sometimes help please!
dolphi86 [110]
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8 0
3 years ago
What would happen if you threw a grenade into a woodchipper?
sammy [17]
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3 0
3 years ago
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A discus thrower turns with angular acceleration of 50 rad/s2, moving the discus in a circle of radius 0.80m. Find the radial an
anyanavicka [17]

Answer:

The value of tangential acceleration \alpha_{t} =  40 \frac{m}{s^{2} }

The value of radial acceleration \alpha_{r} = 80 \frac{m}{s^{2} }

Explanation:

Angular acceleration = 50 \frac{rad}{s^{2} }

Radius of the disk = 0.8 m

Angular velocity = 10 \frac{rad}{s}

We know that tangential acceleration is given by the formula \alpha_{t} = r \alpha

Where r =  radius of the disk

\alpha = angular acceleration

⇒ \alpha_{t} = 0.8 × 50

⇒ \alpha_{t} = 40 \frac{m}{s^{2} }

This is the value of tangential acceleration.

Radial acceleration is given by

\alpha_{r} = \frac{V^{2} }{r}

Where V = velocity of the disk = r \omega

⇒ V = 0.8 × 10

⇒ V = 8 \frac{m}{s}

Radial acceleration

\alpha_{r} = \frac{8^{2} }{0.8}

\alpha_{r} = 80 \frac{m}{s^{2} }

This is the value of radial acceleration.

7 0
4 years ago
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