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aleksandr82 [10.1K]
3 years ago
5

A statue is made of bronze, which is an alloy of about 80% copper and 20% tin. Which metal is in the higher concentration in thi

s bronze statue?
Physics
1 answer:
MAXImum [283]3 years ago
7 0
Copper is the higher concentrated metal in this case.
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After release of jet, energy is lost by the engine. How principle of conservation of energy is obeyed in this condition.​
HACTEHA [7]

Answer:

The principle of conservation of energy states that in a closed system, the energy can neither be created nor destroyed between interacting particles and remains constant or transformed from one form to another

In the jet engine, the release of jet changes the number of interacting particles in the engine, and given that energy cannot be created in the instantaneously closed system of the engine, energy is carried away and therefore lost by particles in the jet exhaust

The conservation of energy principle is therefore obeyed in the condition in which the jet engine losses energy by the release of jet

Explanation:

5 0
3 years ago
A baseball player hits a baseball with a bat. The mass of the ball is 0.25 kg. The ball accelerates at 200 m/s2. What is the for
Brums [2.3K]

Answer:

50N

Explanation:

Force (N) = mass (kg) × acceleration (m/s²)

0.25kg times 200m/s² = 50N

6 0
3 years ago
Consider an oblique shock wave with a wave angle of 35 o . Upstream of the wave, the static pressure and temperature are 2,000 l
ziro4ka [17]

Answer:

The pressure is 6570  lbf/ft²

The temperature is 766 ⁰R

The velocity is 2746.7 ft/s

deflection angle behind the wave is 17.56⁰

Explanation:

Speed of air at initial condition:

a_1 = \sqrt{\gamma RT } =  \sqrt{1.4* 1716*520 } = 1117.70 \ ft/s

γ is the ratio of specific heat, R is the universal gas constant, and T is the initial temperature.

initial mach number

M_1 = \frac{v_1}{a_1} = \frac{3355}{1117.7}  = 3

then, M_n = M_1sin \beta = 3sin(35) = 1.721

based on the values obtained, read off the following from table;

P₂/P₁ = 3.285

T₂/T₁ = 1.473

Mₙ₂ = 0.6355

Thus;

P₂ = 3.285P₁ = 3.285(2000) = 6570  lbf/ft²

T₂ = 1.473T₁ = 1.473(520⁰R) = 766 ⁰R

Again; to determine the velocity and deflection angle, first we calculate the mach number.

M_t_1 = M_1cos \beta = 3 cos(35) = 2.458

w_2 = a_1M_t_1 = 2.458(1117.70) = 2746.7 \ ft/s

a_2 = \sqrt{\gamma RT_2} = \sqrt{1.4*1718*766} = 1357.34 \ ft/s

v_2 = a_2M_n_2 = 1357.34(0.6355) = 862.59 \ ft/s

Tan(\beta -\theta) = \frac{v_2}{w_2} = \frac{862.59}{2746.7}  \\\\Tan(\beta -\theta) = 0.314\\\\\beta -\theta= 17.44\\\\\theta = \beta - 17.44 = 17.56^o

6 0
4 years ago
A rectangular beam 10 cm wide, is subjected to a maximum shear force of 50000 N, the corresponding maximum shear stress being 3
nika2105 [10]

Answer:

Option B is the correct answer.

Explanation:

Shear stress is the ratio of shear force to area.

We have

       Shear stress = 3 N/mm² = 3 x 10⁶ N/m²

       Area = Area of rectangle = 10 x 10⁻² x d = 0.1d

       Shear force = 50000 N

Substituting

        \texttt{Shear stress}=\frac{\texttt{Shear force}}{\texttt{Area}}\\\\3\times 10^6=\frac{50000}{0.1d}\\\\d=0.1667m=16.67cm

Width of beam = 16.67 cm

Option B is the correct answer.

6 0
3 years ago
You are pushing a cart across the room, and the cart has wheels at the front and the back. Your hands are placed on top of the c
Marizza181 [45]

Answer:

The normal force is the force that the floor does as a reaction of the gravitational force that an object does against the floor (is the resistance that objects have when other objects want to move trhough them, and the force comes by the 3rd Newton's law, and this is specially used in cases where the first object is fixed, like walls or the floor). With this in mind, the point in where the normal force will be greater is the point that is closer to the center of mass of the object (the point with more mass)

If the wheels are in the extremes of the object, and the center of mass is in the middle of the object, the normal force will be equal. Now if for example, you put a little mass in one end of the object, now the center of weight displaces a little bit and is not centered, and the side is where you put the weight on will receive a bigger normal force from the floor than the other side.

6 0
3 years ago
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