Question

A truck is traveling 20m/s accelerates 3 m/s^2 for 4 seconds how far did it travel while it was accelerating. Using guess method

Answer 1

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Given

$\blue\star$ v = 20m\s

$\blue\star$ a = 3m\s^2

$\blue\star$ t = 4sec

Firstly we have to find u

$\star$ a = $\dfrac{v - u}{t}$

$\star$ 3m\s =$\dfrac{20 - u}{4}$

$\star$12m\s = 20 - u

$\star$20 - u = 12m\s

$\star$- u = -8

$\star$ u = 8

Now we can easily find distance by using second equation of motion

$\red\star$s = ut + 1\2 at^2

$\red\star$s = 8(4) + 1\2(3)(16)

$\red\star$s = 32 + 24

$\red\star$s = 56

So distance is 56 m\s hope it helps