I need help with the questions when it says what is the topic and rest

A container has 79000cm3 of mercury. Find the mass of mercury if the density is 13.6g/cm3

ZanzabumX [31]

Explanation:

Density is mass divided by volume:

D = M / V

Given V = 79000 cm³ and D = 13.6 g/cm³:

13.6 g/cm³ = M / (79000 cm³)

M = 1,074,400 g

M = 1,074 kg

Round as needed.

6 0

3 years ago

Parallax of the stars is created by

k0ka [10]

Parallax of the stars is created by :
B. Different locations of Earth in its orbit
Parallax refer to the position of an object (in this case, a star) that will look different if we view it from different positions

hope this helps

4 0

4 years ago

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Which of the following is defined as a force that pushes and pulls the current through the circuit? Group of answer choices D) r

Oksi-84 [34.3K]

Answer:

C voltage

Explanation:

Voltage is the change in electric potential so basically current flows from high potential to low potential due to voltage.

5 0

3 years ago

A jet plane traveling 1890 km/h (525 m/s) pulls out of a dive by moving in an arc of radius 5.20 km. What is the plane's acceler

Tema [17]

Answer:

Acceleration of the plane, a = 5.4 g

Explanation:

It is given that,

Speed of the jet plane, v = 1890 km/h = 525 m/s

Radius of the arc, r = 5.20 km = 5200 m

The plane is moving in the circular path, the centripetal acceleration will act on it. It is given by :

$a=\dfrac{v^2}{r}$

$a=\dfrac{(525\ m/s)^2}{5200\ m}$

$a=53.004\ m/s^2$

We know that, the value of g is, $g=9.8\ m/s^2$

$\dfrac{a}{g}=\dfrac{53.004\ m/s^2}{9.8\ m/s^2}=5.4$

$a=5.4\times g$

So, the acceleration of the plane is 5.4 g. Hence, this is the required solution.

6 0

3 years ago

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Which of the following describes one of the main features of wave-particle duality?

steposvetlana [31]

<h2>Answer: as mass increases, the wave nature of matter is less easy to observe.</h2>

At the beginning of the 20th century the French physicist Louis De Broglie proposed the existence of matter waves, that is to say that <u>all matter has a wave associated with it.</u>

In this sense, the de Broglie wavelength $\lambda$ is given by the following formula:

$\lambda=\frac{h}{p}$ (1)

Where:

$h$ is the Planck constant

$p$ is the momentum of the atom, which is given by:

$p=m.v$ (2)

Where:

$m$ is the mass

$v$ is the velocity

Substituting (2) in (1):

$\lambda=\frac{h}{m.v}[\tex] (3)As we can see, if we increase the mass, the wavelength decreases (because [tex]\lambda$ is inversely proportional to $m$ ).

Therefore, if the wavelength decreases the wave nature of matter is less easy to observe.

The other options are incorrect because:

a) as $v$ increases $\lambda$ decreases and the particle nature matter becomes more evident

b) as $p$ decreases $\lambda$ increases and the wave nature matter becomes more evident

c) There is also a relation between the wavelength and the energy $E$ :

$\lambda=\frac{hc}{E}$

So, as energy increases, the particle nature matter becomes more evident and the wave nature of matter becomes harder to observe

8 0

4 years ago