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fenix001 [56]
4 years ago
7

The average atomic mass of oxygen is 15.9994 amu. The atomic masses of its three isotopes are as follows: O-16: 15.995 amu; O-17

: 16.999 amu; O-18: 17.999 amu Which isotope is most likely to have the greatest abundance in nature? O–16 O–17 O–18 all three isotopes may be equally abundant
Chemistry
1 answer:
motikmotik4 years ago
7 0
The average atomic mass of oxygen is the atomic mass with respect to 1/12th the mass of a C-12 atom, related to natural abundance. 
amu - atomic mass units 
O-16 - 15.995 amu
O-17 - 16.999 amu
O-18 - 17.999 amu
the average atomic mass is 15.9994 amu
average atomic mass = ∑atomic mass of each isotope * relative abundance percentage
in other words the average atomic mass is closer to the atomic mass of the most abundant isotope. In this case 15.9994 is closest to 15.995 amu which is the atomic mass of O-16.
This means that O-16 is the most abundant isotope.

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So the answer is that for all other samples the compound X should hold this ration true.

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3 years ago
How many atoms are in 2.5 moles of beryllium atoms?
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3 years ago
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8 0
3 years ago
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Select all of the elements that are classified as metals.
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4 0
3 years ago
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If you had 240 L container at 479 k and 300 kpa, what would the volume be if you changed the conditions to STP
nydimaria [60]

Answer:

The answer to your question is V2 = 434.7 l

Explanation:

Data

Volume 1 = V1 = 240 l                             Volume 2 = ?

Temperature 1 = T1 = 479°K                   Temperature 2 = T2 = 293°K

Pressure 1 = P1 = 300 KPa                      Pressure 2 = P2 = 101.325 Kpa

Process

1.- Use the combined gas law to solve this problem

                P1V1/T1 = P2V2/t2

-Solve for V2

               V2 = P1V1T2 / T1P2

2.- Substitution

                V2 = (300)(240)(293) / (479)(101.325)

3.- Simplification

                V2 = 21096000 / 48534.675

4.- Result

                V2 = 434.7 l

6 0
3 years ago
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