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Artemon [7]
3 years ago
13

A boy climbs 12.0m up an apple tree. He picks an apple and throws it horizontally with a velocity of 3.0 m/s. How far forward do

es the ball go before it hits the ground
Physics
1 answer:
monitta3 years ago
3 0

Answer:

4.692m

Explanation:

The distance that this boy climbed = 12.0m

The velocity = 3.0m/s

We are to find how far forward this apple goes before it hits the ground.

We have y = 1/2gt²

X = v*t

T = 1.564 seconds

X = 3x1.564

X = 4.692m

Therefore the ball goes a distance of 4.692m forward before it then hits the ground.

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A 50-gram sample of water is initially at a temperature of 22 °C. The sample is heated until the temperature is 32 °C The specif
forsale [732]

Answer:

500cal

Explanation:

Given parameters:

Mass of water  = 50g

Initial temperature  = 22°C

Final temperature  = 32°C

Specific heat of water  = 1cal/g

Unknown:

Amount of heat absorbed by the water in calories  = ?

Solution:

To solve this problem, we use the expression below:

       H  = m c Ф

H is the amount of heat absorbed

m is the mass

c is the specific heat capacity

Ф is the temperature change

       H  = 50 x 1 x (32  - 22)  = 500cal

5 0
3 years ago
How do you find the kinetic energy of an object? ​
Sergeeva-Olga [200]

Answer:

KE = 1/2 * m * v^{2}

Explanation:

use the formula:

KE = 1/2 * m * v^{2}

KE = kinetic energy in joules (J)

m = mass in kg

v = velocity in m/s

5 0
3 years ago
Read 2 more answers
Water at a gauge pressure of 3.8 atm at street level flows into an office building at a speed of 0.68 m/s through a pipe 5.4 cm
Nataliya [291]
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7 0
3 years ago
Two boxes of masses m=35kg and m2=45kg, are hung vertically from opposite ends of a rope passing over a rigid horizontal metal r
Over [174]

Answer:

a) 5.51m/s² b) 192.94N c) 1.38m each

Explanation:

Given two boxes of masses m1 = 35kg and m2 = 45kg hung vertically from opposite ends of a rope passing over a rigid horizontal metal rod, we will analyze the forces acting on each body.

According Newton's second law, Force = mass ×acceleration

The forces acting on body of mass m1 are the tension (T) and the frictional force (Ff) which opposes the tension.

Taking the sum of horizontal forces acting on mass m1, we will have;

T +(-Ff) = m1a

T - Ff = m1a... (1)

For the mass m2, the forces acting on the body are in the vertical direction and this forces are the weight (W) acting downwards and the tension(T) acting upwards. The sum of the forces in the body is given as ;

W + (-T) = m2a

W-T = m2a ...(2)

Since W = mg, equation 2 will become;

m2g - T = m2a...(2)

Solving equation 1 and 2 simultaneously to get the tension and the acceleration, we have;

T - Ff = m1a ... 1

m2g - T = m2a ... 2

Since friction is negligible, Ff = 0

Adding the two equation will give;

m2g-Ff = m2a+m1a

Since Ff =0

m2g = (m2+m1)a

a = m2g/m1+m2

a = 45(9.8)/45+35

a =441/80

a = 5.51m/s²

b) Substituting a = 5.51 into equation 1 to get the tension T in the rope will give;

T = m1a

T = 35×5.51

T = 192.94N

c) since velocity = displacement/time

Displacement = velocity × time

To get the velocity, since acceleration = velocity/time,

Velocity = acceleration ×time

Velocity = 5.51× 0.5

Velocity = 2.76m/s

Displacement of each box will be the same since they are moving with the same acceleration.

Displacement = 2.76m/s × 0.5s

Displacement of each boxes = 1.38m

7 0
3 years ago
What is the magnitude of a the displacement vector for a woman who runs 915 m West and then turns and goes 681 m North.
Sladkaya [172]

Answer: 1141km

Explanation:

Given the following :

Distance due west = 915m

Distance due North = 681m

The magnitude of the Displacement =?

The information above produces a right angle triangle and the magnitude of the displacement can be calculated using Pythagoras rule :

The Magnitude of the woman's Displacement represents the hypotenuse of the triangle:

From Pythagoras :

Hypotenus = √(opposite)^2 + (adjacent)^2

Hypotenus = √(915)^2 + (681)^2

Hypotenuse = √1300986

Hypotenuse= 1140.6077

The magnitude of woman's displacement =  1140.6077 = 1141(to the nearest kilometer).

7 0
3 years ago
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