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Ray Of Light [21]
3 years ago
8

In order to be considered a vector, a quantity must include what two components? A. Magnitude

Physics
2 answers:
kaheart [24]3 years ago
5 0

Answer:

Magnitude and direction.

Explanation:

There are two types of physical quantity first one is vector and other is scalar.

Vectors are those physical quantities that have both magnitude as well as direction. Scalars are that type of physical quantities having only magnitude.

Some of the examples of vector quantities are velocity, acceleration, force etc.

So, in order to be considered a vector, a quantity must include its magnitude as direction.

shepuryov [24]3 years ago
3 0

In order to be considered a vector, a quantity must include Magnitude (A) and Direction (D).

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An object is accelerating if it is moving____. circle all that apply. ​
tino4ka555 [31]

Answer:

With changing speed and/or in a circle

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3 years ago
Scientists are making plans to put a probe in orbit around Earth. They want the probe to enter the orbit shown below.
iris [78.8K]

An arrow which shows the direction that the probe should be moving in order for it to enter the orbit is X.

<h3>What is an orbit?</h3>

An orbit can be defined as the curved path through which a astronomical (celestial) object such as planet Earth, in space move around a Moon, Sun, planet or star.

In this scenario, if the scientists want the probe to enter the orbit they should ensure that probe moves in direction X. This ultimately implies that, the probe must move in the same direction as the orbit, in order to enter it.

Read more on orbit here: brainly.com/question/18496962

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2 years ago
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The pressure of a sample of gas is measured as 49 torrent. Convert this to atmosphere ​
spin [16.1K]

Answer:

P = 0.0644 atm

Explanation:

Given that,

The pressure of a sample of gas is measured as 49 torr.

We need to convert this temperature to atmosphere.

The relation between torr and atmosphere is as follow :

1 atm = 760 torr

1 torr = (1/760) atm

49 torr = (49/760) atm

= 0.0644 atm

Hence, the presssure of the sample of gas is equal to 0.0644 atm.

5 0
2 years ago
The forces acting on a leaf are
otez555 [7]

Affected plants

Explanation:

8 0
3 years ago
A block of mass m=1.2 kg is held at rest against a spring with a force constant k=730N/m. Initially the spring is compressed a d
igor_vitrenko [27]

Answer:

Explanation:

potential energy of compressed spring

= 1/2 k d²

= 1/2 x 730 d²

= 365 d²

This energy will be given to block of mass of 1.2 kg in the form of kinetic energy .

Kinetic energy after crossing the rough patch

= 1/2 x 1.2 x 2.3²

= 3.174 J

Loss of energy

= 365 d² - 3.174  

This loss is due to negative work done by frictional force

work done by friction = friction force x width of patch

= μmg d ,   μ = coefficient of friction , m is mass of block , d is width of patch

= .44 x 1.2 x 9.8 x .05

= .2587 J

365 d² - 3.174   = .2587

365 d² = 3.4327

d² = 3.4327 / 365

= .0094

d = .097 m

= 9.7 cm

If friction increases , loss of energy increases . so to achieve same kinetic energy , d will have to be increased so that initial energy increases so compensate increased loss .

5 0
3 years ago
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