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frosja888 [35]
3 years ago
10

Based on this how many Carbon Atoms would be on the products Side

Physics
1 answer:
pashok25 [27]3 years ago
8 0
Please clarify the question, and add more information before I can answer that, I’d need to know the amount of carbon atoms.
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A technician builds an RLC series circuit which includes an AC source that operates at a fixed frequency and voltage. At the ope
MariettaO [177]

Answer:

Xc = (0.467 - 0.427j)R

Explanation:

Since the resistance in the circuit is R, the reactance of the inductor is XL and the reactance of the capacitor is XC, then the impedance of the circuit is

Z = √[R² + (XL - XC)²]

Since the inductive reactance XL equals the resistance R, we have that

Z = √[R² + (XL - XC)²]

Z = √[R² + (R - XC)²]

Thus, the current in the circuit is thus I = V/Z = V/√[R² + (R - XC)²]

Now, when the plate separation of the parallel plate capacitor is reduced to one-half its original value, the current doubles. Also, when the plate separation is reduced to half, the capacitance doubles since C ∝ 1/d where C is capacitance and d separation between the plates. Since the capacitance doubles, the new reactance XC' is twice the initial reactance XC. So, XC' = 2XC. Thus the new impedance is thus

Z' = √[R² + (R - XC')²]

Z' = √[R² + (R - 2XC)²]

The new current is I' = V/Z' = V/√[R² + (R - 2XC)²]

Since the current doubles, I' = 2I.

V/√[R² + (R - 2XC)²] = 2V/√[R² + (R - XC)²]

1/√[R² + (R - 2XC)²] = 2/√[R² + (R - XC)²]

√[R² + (R - XC)²] = 2√[R² + (R - 2XC)²]

squaring both sides, we have

[R² + (R - XC)²] = 4[R² + (R - 2XC)²]

expanding the brackets, we have

[R² + R² - 2RXC + XC²] = 4[R² + R² - 4RXC + 4XC²]

[2R² - 2RXC + XC²] = 4[2R² - 4RXC + 4XC²]

2R² - 2RXC + XC² = 8R² - 16RXC + 16XC²

collecting like terms, we have

16RXC - 2RXC + XC² - 16XC² = 8R² - 2R²

14RXC - 15XC² = 6R²

15XC² - 14RXC + 6R² = 0

Using the quadratic formula to find XC, we have

XC = \frac{-(-14R) +/- \sqrt{(-14R)^{2} - 4 X 15 X 6R^{2} } }{2 X 15}\\= \frac{-(-14R) +/- \sqrt{196R^{2} - 360R^{2} } }{30}\\ \\= \frac{14R +/- \sqrt{- 164R^{2} } }{30}\\ \\= \frac{14R +/- 12.81Ri }{30}\\\\= 0.467R +/- 0.427Ri

Since it is capacitive, we take the negative part.

So, Xc = (0.467 - 0.427j)R

4 0
3 years ago
Why might a volcanic eruption lead to cooler temperatures over a large area around the volcano
wel
Because of ash clouding the sky, blocking sunlight for a while.
8 0
3 years ago
A +2.2 x 10-9 C charge is on the axis ar x= 1.5 m, a +5.4 x 10-9 C charge is on the x-axis at x= 2.0 m, and a+3.5 x 10-9 C charg
lisov135 [29]

The net force on the charge at the origin is -1.2×10-8

<u>Explanation:</u>

Solving the problem,

  • Draw the x-axis and the locations of the given three charges.
  • The forces applied on the charge at the origin and there are two of them, and since all the changes are positive, all the forces are repulsive.
  • we have the formula, F = kq1Q/r².
  • F1 = kq1Q/r²1 = (9.0*109Nm²/C²)(2.2*10^-9C)(3.5*10^-9C)/(1.5m)² = 31*10-9N = 3.1*10-8N.  F1 points to the right (+x direction).
  • F2 = kq2Q/r²2 = (9.0*109Nm²/C²)(5.4*10^-9C)(3.5*10^-9C)/(2.0m)² = 43*10^-9N = 4.3*10^-8N.
  • F2 points to the left (-x direction).
  • To find the net force we have to subtract the force F1 and force F2 .
  • The net force is F(origin) = F1 - F2 = -1.2×10-8N.

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5 0
3 years ago
What is necessary for fossil fuels to form? oxygen forming continuously for a long period of time sunlight shining continuously
Oksanka [162]
Heat and pressure acting over a long period of time
4 0
3 years ago
Read 2 more answers
Does hot water or cold water boil faster is that repeated observations using models are controlled experiments
lozanna [386]
Hot water boils faster since its already hot and dosnt take much more time to get as hot
4 0
3 years ago
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