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Arada [10]
3 years ago
7

gravity is a force between any two objects with mass. why doesn't a person feel a gravitational force between him/herself and an

other person?a)a person doesn't exert a gravitational force.b)the two gravitational forces cancel each other out.c)the gravitational forces of people is so small it is overshadowed by that of earth.d)there are so many people we are actually balanced by all the different gravitational forces.
Physics
2 answers:
Doss [256]3 years ago
7 0
If you and your brother both have 70 kg of mass, then . . .

-- you both weigh about 154 pounds on Earth.

-- You both weigh about 25 pounds on the Moon.

-- If you stand about 2 meters (6-1/2 feet) apart, then the force
of gravity pulling you together is about  8.2 x 10⁻⁸ newton.

That's about  0.00000029 ounce.

THAT's why.

The correct choice is 'c'.
antiseptic1488 [7]3 years ago
4 0

Answer:

c)the gravitational forces of people is so small it is overshadowed by that of earth.

Explanation:

The gravitational force between two objects is given by:

F=G\frac{m_1 m_2}{r^2}

where

G is the gravitational constant

m1 and m2 are the masses of the two objects

r is the distance between the two objects

From the formula, we see that the gravitational force depends on the masses of the objects: since the mass of the Earth (5.97\cdot 10^{24} kg is much much larger than the average mass of one person (80-100 kg), then the gravitational force exerted by the Earth on a person is also much much larger than the gravitational force between two people.

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A proton (mass m = 1.67 × 10-27 kg) is being accelerated along a straight line at 2.50 × 1012 m/s2 in a machine. If the proton h
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Answer:

(A) Speed will be 44.18\times 10^4m/sec

(b) Change in kinetic energy = 1560\times 10^{-19}      

Explanation:

We have given mass of proton m=1.67\times 10^{-27}kg

Acceleration of the proton a=2.50\times 10^{12}m/sec^2

Initial velocity u = 1.60\times 10^4 m/sec

Distance traveled by proton s = 3.90 cm = 0.039 m

(a) From third equation of motion we know that

v^2=u^2+2as

v^2=(1.60\times 10^4)^2+2\times 2.5\times 10^{12}\times 0.039

v=44.18\times 10^4m/sec

(b) Initial kinetic energy KE_I=\frac{1}{2}mv^2=\frac{1}{2}\times 1.67\times 10^{-27}\times (1.6\times 10^4)^2

Final kinetic energy KE_F=\frac{1}{2}mv^2=\frac{1}{2}\times 1.67\times 10^{-27}\times (44.18\times 10^4)^2

So change in kinetic energy \Delta KE=KE_F-KE_I=\frac{1}{2}\times 1.6\times 10^{-27}\times 10^8\times (44.18^2-1.6^2)=1560\times 10^{-19}J

6 0
3 years ago
Is frequent anger a problem for you? If so, what strategies could you try to<br> overcome it?
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Explanation:

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Is it possible for a car to be accelerating to the west while it is driving to the east?
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8 0
3 years ago
A 2.1 kg block is dropped from rest from a height of 5.5 m above the top of the spring. When the block is momentarily at rest, t
ella [17]

Answer:

The speed of the block is 8.2 m/s

Explanation:

Given;

mass of block, m = 2.1 kg

height above the top of the spring, h = 5.5 m

First, we determine the spring constant based on the principle of conservation of potential energy

¹/₂Kx² = mg(h +x)

¹/₂K(0.25)² = 2.1 x 9.8(5.5 +0.25)

0.03125K = 118.335

K = 118.335 / 0.03125

K = 3786.72 N/m

Total energy stored in the block at rest is only potential energy given as:

E = U = mgh

U = 2.1 x 9.8 x 5.5 = 113.19 J

Work done in compressing the spring to 15.0 cm:

W = ¹/₂Kx² = ¹/₂ (3786.72)(0.15)² = 42.6 J

This is equal to elastic potential energy stored in the spring,

Then, kinetic energy of the spring is given as:

K.E = E - W

K.E = 113.19 J - 42.6 J

K.E = 70.59 J

To determine the speed of the block due to this energy:

KE =  ¹/₂mv²

70.59 =  ¹/₂ x 2.1 x v²

70.59 = 1.05v²

v² = 70.59 / 1.05

v² = 67.229

v = √67.229

v = 8.2 m/s

8 0
3 years ago
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