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lorasvet [3.4K]
3 years ago
6

Explain what happens to particles in diffusion. What causes diffusion?

Physics
2 answers:
vlabodo [156]3 years ago
8 0
<u><em>Diffusion:
</em></u><em> in diffusion particles move from area of higher concentration to the area of lower concentration..
</em><u><em>causes:
</em></u><em>the movement of particles allow them ti disperse,,, when molecules are close to each other they collide with each other and push each other apart so they spread in the whole area... :)</em><u><em>
</em></u>
ankoles [38]3 years ago
5 0
 Diffusion is the process of water molecules from a high concentration region to low concentration.When particles diffuse ,they will break down to simpler particles.
<u>Causes:
</u>Due to the motion of paticles the particles will collide each other and mix.
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a college student rests a backpack upon his shoulder. the pack is suspended motionless by one strap from one shoulder.
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The student's shoulder supports the weight of the bag.

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1 year ago
Five moles of an ideal monatomic gas with an initial temperature of 121 ∘C expand and, in the process, absorb an amount of heat
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  T₂ ≈ 107.85∘C

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The question didn't state if the volume is constant or not as such, we can apply the first law of thermodynamic

From the first law of thermodynamic,

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where ΔU = Internal Energy, Q = Quantity of heat absorbed, W = Amount of work done.

Q = 1200 J and W = 2020 J

∴ ΔU = 1200 -2020 = -820 J.

Using the ideal gas equation,

ΔU = 3/2nRΔT...................................equation 1

where n = number of moles, R = Molar gas constant, ΔT = Change in temperature = (T₂ - T₁).

Modifying equation 1,

ΔU = 3/2nR(T₂ -T₁)...............................equation 2.

making T₂ the subject of the relation in equation 2,

T₂ =  {2/3(ΔU)/nR}+T₁........................ equation 3

where T₁=121∘C, R= 8.314 J / mol, n=5 moles, ΔU=-820 J

Substituting these values into equation 3,

∴ T₂ ={ 2/3(-820)/(5×8.314)}+121

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 ∴T₂  = 121 - 13.151 = 107. 849∘C

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