She did not have a control group, and she did not expose all three samples to wind. Because her hypothesis was a combination of things, she needed to test the different combinations.
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<span>I believe this question has additional detail which stated
that during the 1st half, his speed was 2.01 m/s. From this we can
calculate his speed during the second half, v2, using the formula:</span>
v_ave = (v1 + v2) / 2
2.05 m/s = (2.01 m/s + v2) / 2
<span>v2 = 2.09 m/s</span>
There are no appropriate units for power on the list you provided
Answer:
Δp = -2 p₀
Explanation:
The momentum is defined by
p = m v
In this case we write the initial and final momentum, we take as positive the direction towards the wall.
p₀ = m v
p_f = m (-v)
the negative sign is because the car is bouncing off the wall
the change of the moment is
Δp = p_f - p₀
Δp = - m v - m v
Δp = -2 mv
Δp = -2 p₀
we see that the change of moment is twice the moment, in the attachment we can see the vectors of these changes and the sign indicates the direction of the change at the moment