The position of the first ball is

while the position of the second ball, thrown with initial velocity
, is

The time it takes for the first ball to reach the halfway point satisfies



We want the second ball to reach the same height at the same time, so that




Answer:
265 J
Explanation:
where KE is kinetic energy, PE is potential energy, m is the mass of an object, v is the speed, h is the height and g is acceleration due to gravity.
Substituting 19.7 Kg for mass, 0.934 for h, 2.93 for v and 9.81 for g then

I think you almost got it.
At the top, the velocity only has horizontal component, so v=12 m/s is v_x, which is v*cos(theta), because v_x is constant, so the same when it was launched or now.
With the value of the initial speed (28 m/s, which is the total speed), you can set
v_x = v * cos( theta ) ---> 12 = 28*cos(theta) --> cos(theta)=12/28=3/7
or theta = 64.62 deg, it is D. Think about it. I hope you see it.
The answer is (a).
Golf balls have a higher density than water hence sink to the bottom.
Answer: The Porsche Wins. Arrives 19secs earlier before the Honda.
Explanation: The head start of 1secs corresponded with the difference in acceleration {3.5m/s² - 3m/s²}=0.5m/s²
Using the first equation of motion we obtain the velocity which correspond to this acceleration (0.5m/s²) and time of 1secs where initial velocity u = 0
V = u + at
V= 0 + at
V = 0.5 * 1 = 0.5m/s
Now let find the velocity of each of the car.
If V. a
0.5m/s 0.5m/s²
........m/s. 3.5m/s²
Velocity of porche Vp
= (3.5/0.5) * 0.5 = 3.5 m/s
Also if. V. a
0.5m/s. 0.5m/s²
.....m/s. 3 m/s²
Velocity of Honda Vh
= {3/0.5} * 0.5 = 3m/s
So let's find the time t taken by both cars to cover the distance of 400m
Recall,
Velocity = distance/time
Time t = distance/velocity
For Porche, t = 400/3.5 =114.29secs
For Honda, t = 400/3 = 133.33secs
Looking critically, we noticed that Porche car took shorter time.
The difference In time is
= (133.33 - 114.29)secs = 19.04secs