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alukav5142 [94]
1 year ago
5

How do you know you are effectively communicating your thoughts to others?

Physics
1 answer:
Bond [772]1 year ago
5 0

5 ways to communicate better

Prepare yourself on the subject. ...

Structure your thoughts. ...

Keep it simple. ...

Listen to others with intent. ...

Engage well.

For an individual to succeed as well as for an organization to succeed, effective communication is crucial. Leaders who can articulate their ideas well are better at motivating and forming bonds with their staff. Furthermore, it's critical to positively and concisely convey your opinions.Whether or not communication is successful determines whether a relationship will succeed. Being able to explain your ideas clearly is only one aspect of effective communication; listening intently is another. It is the capacity to completely comprehend, to demonstrate empathy, and to provide feedback in light of the other person's answer. Simply said, it is the fruitful interchange of ideas and opinions between individuals or organizations.

Learn more about communication here:

brainly.com/question/25793182

#SPJ9

-

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A man on the moon with a mass of 90 kilograms weighs 146 newtons. The radius of the moon is 1.74 x 106 meters, find the mass of
melisa1 [442]

Answer:

7.36 × 10^22 kg

Explanation:

Mass of the man = 90kg

Weight on the moon = 146N

radius of the moon =1.74×10^6

Weight =mg

g= weight/mass

g= 146/90 = 1.62m/s^2

From the law of gravitational force

g = GM/r^2

Where G = 6.67 ×10^-11

M = gr^2/G

M= 1.62 × (1.74×10^6)^2/6.67×10^-11

= 4.904×10^12/6.67×10^-11

=0.735×10^23

M= 7.35×10^22kg. (approximately) with option c

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2 years ago
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anzhelika [568]

Answer:

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2 years ago
When a pair of balanced forces acts on an object, the net force that results is.
polet [3.4K]
D.  Equal to zero.

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koban [17]

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A 2.0-kg object moving with a velocity of 5.0 m/s in the positive x direction strikes and sticks to a 3.0-kg object moving with
Andrej [43]

Answer:

5.4 J.

Explanation:

Given,

mass of the object, m = 2 Kg

initial speed, u = 5 m/s

mass of another object,m' = 3 kg

initial speed of another orbit,u' = 2 m/s

KE lost after collusion = ?

Final velocity of the system

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2 x 5 + 3 x 2 = ( 2 + 3 )V

16 = 5 V

V = 3.2 m/s

Initial KE = \dfrac{1}{2}mu^2 + \dfrac{1}{2}m'u'^2

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Final KE = \dfrac{1}{2} (m+m')V^2 = \dfrac{1}{2}\times 5 \times 3.2^2 = 25.6 J

Loss in KE = 31 J - 25.6 J = 5.4 J.

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