Answer:
7.36 × 10^22 kg
Explanation:
Mass of the man = 90kg
Weight on the moon = 146N
radius of the moon =1.74×10^6
Weight =mg
g= weight/mass
g= 146/90 = 1.62m/s^2
From the law of gravitational force
g = GM/r^2
Where G = 6.67 ×10^-11
M = gr^2/G
M= 1.62 × (1.74×10^6)^2/6.67×10^-11
= 4.904×10^12/6.67×10^-11
=0.735×10^23
M= 7.35×10^22kg. (approximately) with option c
D. Equal to zero.
Because the forces balance each other.
C. making fun of a peer because she is Asian
hope this helps
Answer:
5.4 J.
Explanation:
Given,
mass of the object, m = 2 Kg
initial speed, u = 5 m/s
mass of another object,m' = 3 kg
initial speed of another orbit,u' = 2 m/s
KE lost after collusion = ?
Final velocity of the system
Using conservation of momentum
m u + m'u' = (m + m') V
2 x 5 + 3 x 2 = ( 2 + 3 )V
16 = 5 V
V = 3.2 m/s
Initial KE = 
= 
= 31 J
Final KE = 
Loss in KE = 31 J - 25.6 J = 5.4 J.