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Novosadov [1.4K]
3 years ago
10

After training for a marathon, you would like to complete your first attempt of the 26.22 mile race in under 4.800 hours. At wha

t pace is the slowest you could run and still finish by your goal time (provide your answer in miles/s)?
Physics
1 answer:
melamori03 [73]3 years ago
8 0

Answer:

<em>1.52 x 10^-3 miles per sec</em>

<em></em>

Explanation:

distance to be covered = 26.22 miles

targeted time = 4.8 hours

4.8 hours in seconds = 4.8 x 60 x 60 = 17280 sec

Speed = distance/time

speed = 26.22/17280 = <em>1.52 x 10^-3 miles per sec</em>

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joja [24]
<span>There is no special name for that. Physics is usually just concerned with "forces", and doesn't specify whether the force pushes or pulls. If you want to be more specific, you can just call it a "pulling force".
I hoped this was satisfying!:)</span>
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The Great Sandini is a 60 kg circus performer who is shotfrom a cannon (actually a spring gun). You don't find many men ofhis ca
d1i1m1o1n [39]

Answer:

V=15.3 m/s

Explanation:

To solve this problem, we have to use the energy conservation theorem:

U_e+K_i+U_{gi}+W_{friction}=K_f+U_{gf}

the elastic potencial energy is given by:

U_e=\frac{1}{2}*k*x^2\\U_e=\frac{1}{2}*1100N/m*(4m)^2\\U_e=8800J

The work is defined as:

W_{friction}=F_f*d*cos(\theta)\\W_{friction}=40N*2.5m*cos(180)\\W_{friction}=-100J

this work is negative because is opposite to the movement.

The gravitational potencial energy at 2.5 m aboves is given by:

U_{gf}=m*g*h\\U_{gf}=60kg*9.8*2.5\\U_{gf}=1470J

the gravitational potential energy at the ground and the kinetic energy at the begining are 0.

8800J+0+0+-100J=\frac{1}{2}*62kg*v^2+1470J\\v=\sqrt{\frac{2(8800J-100J-1470J)}{62kg}}\\v=15.3m/s

3 0
3 years ago
How many protons are in this atom if it has a balanced charge
Lerok [7]
It would be 20 protons left because 1-19= 20
7 0
2 years ago
A man at point A directs his rowboat due north toward point B, straight across a river of width 100 m. The river current is due
prohojiy [21]

Answer:

1.35208 m/s

Explanation:

Speed of the boat = 0.75 m/s

Distance between the shores = 100 m

Time = Distance / Speed

Time=\frac{100}{0.75}=133.33\ s

Time taken by the boat to get across is 133.33 seconds

Point C is 150 m from B

Speed = Distance / Time

Speed=\frac{150}{\frac{100}{0.75}}=1.125\ m/s

Velocity of the water is 1.125 m/s

From Pythagoras theorem

c=\sqrt{0.75^2+1.125^2}\\\Rightarrow c=1.35208\ m/s

So, the man's velocity relative to the shore is 1.35208 m/s

3 0
3 years ago
An automobile tire is rated to last for 35,000 miles. to an order of magnitude, through how many revolutions will it turn?
Furkat [3]
<span>The tire will rotate about 10 million times. An automobile tire is slightly less than 2 and half feet in diameter. It's circumference is that times pi with is a bit over 3. So 2.5 * 3 = 7.5 ft as an estimate for how far the tire rolls per revolution. A mile is a bit over 5000 feet, so call it 700 revolutions per mile. For the 35000 miles, call it 7 times 5000 miles. Now 7 times 7 is a bit under 50, so call 7 * 700 = 5000. And 5000 times 5000 = 25000000. The nearest order of magnitude is 10 million. So as an order of magnitude estimate, a automobile tire will rotate about 10 million times during it's life.</span>
7 0
3 years ago
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