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Novosadov [1.4K]
3 years ago
10

After training for a marathon, you would like to complete your first attempt of the 26.22 mile race in under 4.800 hours. At wha

t pace is the slowest you could run and still finish by your goal time (provide your answer in miles/s)?
Physics
1 answer:
melamori03 [73]3 years ago
8 0

Answer:

<em>1.52 x 10^-3 miles per sec</em>

<em></em>

Explanation:

distance to be covered = 26.22 miles

targeted time = 4.8 hours

4.8 hours in seconds = 4.8 x 60 x 60 = 17280 sec

Speed = distance/time

speed = 26.22/17280 = <em>1.52 x 10^-3 miles per sec</em>

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How much work does it take to move a 50 μC charge<br> against a 12 V potential difference?
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2 years ago
A punter wants to kick a football so that the football has a total flight time of 4.70s and lands 56.0m away (measured along the
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Answer:

Explanation:

How long does the football need to rise?

4.70/3 = 2.35 s

What height will the football reach?

h = ½(9.81)2.35² = 27.1 m

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vy = g•t = 9.81(2.35) = 23.1 m/s

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At what angle (θ), with the horizontal, does the punter need to kick the football?

θ = arctan(vy/vx) = 62.7°

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2 years ago
If you pull horizontally on a desk with a force of 150 N and the desk doesn't move, the friction force must be 150 N. Now if you
s344n2d4d5 [400]

Answer:

The friction force is 250 N

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The desk is moving at constant velocity. This means that its acceleration is zero: a = 0. Newton's second law states that the resultant of the forces acting on the desk is equal to the product between mass (m) and acceleration (a):

\sum F=ma

In this case, we know that the acceleration is zero: a = 0, so also the resultant of the forces must be zero:

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We are only interested in the forces acting along the horizontal direction, since it is the direction of motion. There are two forces acting in this direction:

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Given (1), we have

F-F_f = 0

So the force of friction must be equal to the pull:

F=F_f = 250 N

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Sure , I'm subscribing!!!

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