F)
size , texture , and color hope this helps
Answer:
Explanation:
The centripetal acceleration requirement must equal gravity at the top of the circle
mg = mv²/R
v = √Rg
v = √(1.0(9.8))
v = 3.1304951...
v = 3.1 m/s
Answer:
Explanation:
We shall apply work energy theorem to calculate the initial velocity just after the collision .
Their kinetic energy will be equal to work done by friction .
force of friction = μ mg , where μ is coefficient of friction , m is total mass and g is acceleration due to gravity
force = .463 x 3210 x 9.8
= 14565.05 N
work done = force x displacement
= 14565.05 x 14.54 = 211775.88 J
now applying work energy theorem
1/2 m v² = 211775.88 , m is composite mass , v is velocity just after the collision
.5 x 3210 x v² = 211775.88
v² = 131.94
v 11.48 m /s
Answer:
See the answers below
Explanation:
In order to solve these problems, we must decompose the magnitudes of the velocities on the x & y-axes, using the angles that are given. It is important for a better understanding to look at the attached image and understand how the angles are located relative to the horizontal axis.
1.
The horizontal component of the angle can be found with the cosine function. While the vertical component can be found using the sine function of the angle.
Viy = 24*sin (40)
Viy = 15.42 [m/s]
2.
The horizontal component of the angle can be found with the cosine function.
Vix = 24*cos(40)
Vix = 18.38 [m/s]
3.
Vix = 55*cos(25)
Vix = 49.84 [m/s]
Momentum equation is
change in momentum = mass•initial velocity•final velocity
so....
p=700(15) because your initial is 30, and your final in 15, so you subtract! hope that helped!