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Alex73 [517]
4 years ago
14

If a man has a mass of 83 kg on Earth what will the force of gravity on his body be on the moon

Physics
2 answers:
mrs_skeptik [129]4 years ago
6 0

Im not sure bro, can you help me

fiasKO [112]4 years ago
3 0
You find the acceleration due to gravity on the moon and multiply it by 83kg
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Kelly is riding a bicycle, moves with an initial velocity of 5 m/s. Ten seconds later, she is moving at 15 m/s. What is her acce
sladkih [1.3K]

Answer:

her acceleration is 1 m/sec

Explanation:

The following information is given in the question

The initial velocity is 5 m/s

After 10 seconds, she would be moved at 15 m/s

We need to find the acceleration

As we know that

Acceleration = Change in speed ÷ time

Acceleration = (15 - 5) ÷ (10)

= 1 m/sec

Hence, her acceleration is 1 m/sec

The same would be considered  

3 0
3 years ago
What properties are different between blue light and red light?
Oksi-84 [34.3K]
Blue light has a shorter wavelength than does red light, and since it travels at the same speed (in vacuum) as red light, has a higher frequency. This gives it a higher energy per photon.
3 0
3 years ago
Jenni wants to start a print shop making specialty papers and cards. Which economic question has she answered?
Artemon [7]
I think it is Letter D, because she already said what to make

5 0
3 years ago
Read 2 more answers
A car of mass 1500 kg travels due East with a constant speed of 25.0 m/s. Eventually it turns right, and travels due South with
e-lub [12.9K]

Answer:

The direction of the car’s change in linear momentum is 149.04° West of North

Explanation:

Momentum is defined as the product of mass of a body and its velocity

Momentum = mass × velocity

Change in Momentum = mass × change in velocity

∆P = m∆v

∆P = m(v-u)

Given m = 1500kg

v = 25m/s

u = 15m/s

∆P = 1500(25-15)

∆P = 1500×10

∆P = 15,000kgm/s

Since the car first travels due East i.e +x direction

x = 25m/s

Travelling due south is negative y direction

y = -15m/s

Direction of the car change

θ = tan^-1(y/x)

θ = tan^-1(-15/25)

θ = tan^-1(-0.6)

θ = -30.96°

Since tan is negative in the second quadrant

θ = 180-30.96

θ = 149.04°

The direction of the car’s change in linear momentum is 149.04° West of North

5 0
4 years ago
Formed through longshore drift<br> a. sea stack<br> b. sandbar<br> c. spit<br> d. headland
ANTONII [103]
<h3>Answer;</h3>

<em><u>Sand Spit or Spit </u></em>

<h3><u>Explanation;</u></h3>
  • <em><u>Long shore drift is the process that occurs when a sheet of water moves on and off the beach, in other words the swash and back swash</u></em>, thus capturing and transporting sediment on the beach back out to the sea.
  • <em><u>Sandbar</u></em> is normally formed when the sandspit stretches across a bay and connects the two sides. <em><u>Headland</u></em> is a high piece of land that extends out onto the sea. <em><u>Sea stacks </u></em>on the other hand results from the collapsing of the roof of the arch.
7 0
4 years ago
Read 2 more answers
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