3 years ago

Please help me out here ASAP. Thanks!

1 answer:

4 0

y - y₁ = m(x - x₁)
y - (-1) = 4[x - (-3)]
y + 1 = 4(x + 3)
y + 1 = 4(x) + 4(3)
y + 1 = 4x + 12
- 1 - 1
y = 4x + 11

The answer is B.

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<h3>How to determine the sum of the series?</h3>

The series is given as:

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Start by calculating the common ratio using:

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