The magnitude of the net force that is acting on particle q₃ is equal to 6.2 Newton.
<u>Given the following data:</u>
Charge = C.
Distance = 0.100 m.
<u>Scientific data:</u>
Coulomb's constant =
<h3>How to calculate the net force.</h3>
In this scenario, the magnitude of the net force that is acting on particle q₃ is given by:
F₃ = F₁₃ + F₂₃
Mathematically, the electrostatic force between two (2) charges is given by this formula:
<u>Where:</u>
- r is the distance between two charges.
<u>Note:</u> d₁₃ = 2d₂₃ = 2(0.100) = 0.200 meter.
For electrostatic force (F₁₃);
F₁₃ = 1.24 Newton.
For electrostatic force (F₂₃);
F₂₃ = 4.96 Newton.
Therefore, the magnitude of the net force that is acting on particle q₃ is given by:
F₃ = 1.24 + 4.96
F₃ = 6.2 Newton.
Read more on charges here: brainly.com/question/14372859
Answer: Solid
Explanation: Most of the outer part of our planet is solid. This solid mantle sits on an outer liquid core and a solid inner core.
Ideal Gas Law is, pV = NkbT
<span>Therefore, p/t = Nkb/V which is
equal to the constant</span>
We need to convert the given temperature to Kelvin. We need to add 273 to
have the Kelvin of the temperature from Celsius.
T1= 20 + 273 = 293 K
T2= 120 + 273 = 393 K
With this we have the pressure ration of 393/293.
So,F120 = 1.34 APa
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