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AleksandrR [38]
3 years ago
10

Use the molar solubility 3.27×10−11m in pure water to calculate ksp for nis.

Chemistry
1 answer:
Ne4ueva [31]3 years ago
4 0

Answer:

Ksp = 1.07x10⁻²¹

Explanation:

Molar solubility is defined as moles of solute can be dissolved in 1L.

Ksp for NiS is defined as:

NiS(s) ⇄ Ni²⁺(aq) + S²⁻(aq)

Ksp = [Ni²⁺] [S²⁻]

As molar solubility is 3.27x10⁻¹¹M, concentration of [Ni²⁺] and [S²⁻] is 3.27x10⁻¹¹M for both.

Replacing:

Ksp = [3.27x10⁻¹¹M] [3.27x10⁻¹¹M]

<em>Ksp = 1.07x10⁻²¹</em>

<em></em>

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Starting from position 3,5 go west 7 , then south 7, then east 4 what’s your ending point?
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-1, -2

Explanation:

West is left south is down east is right

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What is the molarity of a solution made by mixing 75.0 mL of 3.00 M NH₄OH with enough water to give 250. mL of solution?
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Answer:

Mass 1=3M

Mass 2=?

Volume1=75mL

Volume2=250mL

By using molarity formula:

<u>mass1*volume 1=mass2*volume 2</u>

3M*75=mass2*250

mass2=225/250

mass2:0.9M

<h3>the molarity of a solution is 0.9M.</h3>
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3 years ago
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Calculate the number of photons that would be contained in a laserpulse with a wavelength of 287 nm that contained 4.35 mJ of en
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3.46 ⋅ 10 − 19 J

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New oceanic lithosphere forms as a result of
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What is the maximum amount of zno (81.4084 g/mol) which could be formed from 12.85 g of zns (97.474 g/mol) and 15.91 g of o2 (31
Inessa05 [86]

Answer:

             8.75 g of ZnO

Solution:

The Balance Chemical Reaction is as follow,

                                 2 ZnS  +   3 O₂    →    2 ZnO  +  2 SO₂  

Step 1: Find out the limiting reagent as;

According to Equation ,

            194.94 g (2 mole) ZnS reacts with  =  96 g (3 moles) of O₂

So,

                  12.85 g of ZnS will react with  =  X g of O₂

Solving for X,

                      X  =  (12.85 g × 96 g) ÷ 194.94 g

                      X  =  6.32 g of O₂

It means for total utilization of 12.85 g of ZnS we require 6.32 g of O₂, but we are provided with 15.91 g of O₂. Therefore, ZnS is the limiting reagent and will control the yield.

Step 2: Calculate Amount of ZnO produced as;

According to Equation ,

              194.94 g (2 mole) ZnS produces  =  132.81 g (2 moles) of ZnO

So,

                       12.85 g of ZnS will produce  =  X g of ZnO

Solving for X,

                      X =  (12.85 g × 132.81 g) ÷ 194.94 g

                      X  =  8.75 g of ZnO

8 0
4 years ago
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