Answer:
Explanation:
The pictures below shows the whole explanation for the problem
Answer:
Option A - fail/ not fail
Explanation:
For this given problem, if the yield strength is now 45 ksi, using Distortion Energy Theory the material will _fail______ and using the Maximum Shear Stress Theory the material will ___not fail_______
Answer:
The required diameter of the fuse wire should be 0.0383 cm to limit the current to 0.53 A with current density of 459 A/cm²
.
Explanation:
We are given current density of 459 A/cm² and we want to limit the current to 0.53 A in a fuse wire. We are asked to find the corresponding diameter of the fuse wire.
Recall that current density is given by
j = I/A
where I is the current flowing through the wire and A is the area of the wire
A = πr²
but r = d/2 so
A = π(d/2)²
A = πd²/4
so the equation of current density becomes
j = I/πd²/4
j = 4I/πd²
Re-arrange the equation for d
d² = 4I/jπ
d = √4I/jπ
d = √(4*0.53)/(459π)
d = 0.0383 cm
Therefore, the required diameter of the fuse wire should be 0.0383 cm to limit the current to 0.53 A with current density of 459 A/cm²
.
Answer:
Driving test
Explanation:
Usually according to laws in countries worldwide, to be licenced to drive, one is required to go through a driving school to learn the ethics and rules of driving.
Explanation:
1. Circumference is pi times diameter.
C = πd
C = 9π inches
C ≈ 28.3 inches
2. Mechanical advantage is ratio of output force to input force.
MA = Fout / Fin
MA = 155 lb / 15 lb
MA ≈ 10.3
3. Mechanical advantage is ratio of input distance over output distance.
MA = din / dout
MA = 10.5 in / 0.85 in
MA ≈ 12.4
4. Mechanical advantage of pulley system is the number of strands.
MA = 8
5. Mechanical advantage is ratio of output force to input force.
MA = Fout / Fin
8 = Fout / 200 lb
Fout = 1600 lb
