Answer:
All the detailed steps are mentioned in pictures.
Explanation:
See attached pictures.
Determine the reactor volume (assume a CSTR activated sludge aerobic reactor at steady state) required to treat 5 MGD of domesti
1 answer:
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Answer:
fracture will occur as the value is less than E/10 (= 22.5)
Explanation:
If the maximum strength at tip Is greater than theoretical fracture strength value then fracture will occur and if the maximum strength is lower than theoretical fracture strength then no fracture will occur.
= 15 GPa
fracture will occur as the value is less than E/10 = 22.5
Answer: 3/2mg
Explanation:
Express the moment equation about point B
MB = (M K)B
-mg cosθ (L/6) = m[α(L/6)](L/6) – (1/12mL^2 )α
α = 3g/2L cosθ
express the force equation along n and t axes.
Ft = m (aG)t
mg cosθ – Bt = m [(3g/2L cos) (L/6)]
Bt = ¾ mg cosθ
Fn = m (aG)n
Bn -mgsinθ = m[ω^2 (L/6)]
Bn =1/6 mω^2 L + mgsinθ
Calculate the angular velocity of the rod
ω = √(3g/L sinθ)
when θ = 90°, calculate the values of Bt and Bn
Bt =3/4 mg cos90°
= 0
Bn =1/6m (3g/L)(L) + mg sin (9o°)
= 3/2mg
Hence, the reactive force at A is,
FA = √(02 +(3/2mg)^2
= 3/2 mg
The magnitude of the reactive force exerted on it by pin B when θ = 90° is 3/2mg
Answer:
Magnitude of the velocity = 16.82 m/s
Angular direction, θ = 52.41°
Explanation:
As given ,
mass of bullet, m₁= 50g = 0.05 kg
speed of bullet , u₁ = 600 m/s
mass of the block , m₂ = 4 kg
speed of the block before collision , u₂ = 12 m/s
direction , θ = 30°
Now,
Assume that the combined velocity of bullet and block after collision = v
and the direction = θ
Now, from the conservation of momentum in x - direction :
m₁ u₁ + m₂ u₂ = ( m₁ + m₂ ) vₓ
where v = final velocity after collision
u₁ = initial velocity of bullet before collision = 0
m₁ = mass of the bullet before collision = 0.05 kg
u₂ = velocity of block before collision = 12 cos(30° )
m₂ = mass of block before collision
m₁ + m₂ = combined mass of bullet and block after collision = 0.05 + 4
∴ we get
0.05 (0) + 4(12 cos(30° ) ) = ( 0.05 + 4 ) vₓ
⇒ 0 + 4(6√3) = 4.05 vₓ
⇒24√3 = 4.05 vₓ
⇒vₓ = 10.26 m/s
Now, from the conservation of momentum in y - direction :
m₁ u₁ + m₂ u₂ = ( m₁ + m₂ )
where v = final velocity after collision
u₁= initial velocity of bullet before collision = 600
m₁ = mass of the bullet before collision = 0.05 kg
u₂ = velocity of block before collision = 12 sin(30° )
m₂= mass of block before collision
m₁+ m₂= combined mass of bullet and block after collision = 0.05 + 4
∴ we get
0.05 (600) + 4(12 sin(30° ) ) = ( 0.05 + 4 )
⇒ 30 + 4(6) = 4.05
⇒30 +24 = 4.05
⇒54 = 4.05
⇒ = 13.33 m/s
Now, the magnitude of the velocity = √vₓ² + ² = √(10.26)² + (13.33)²
= √105.26 + 177.68
= √282.95 = 16.82
The angular direction, θ = (
) =
(
) =
(1.299) = 52.41°
Answer:
Current Relative Humidity is 29.623
Given:
Current Temperature,
Dew point temperature,
Solution:
Now, in order to calculate the Relative Humidity, RH, we use the given formula:
where
a = 17.625
b = 237.7
Now, using the above formula and given values:
On solving the above eqn, we get:
RH = 29.623