Answer:
a) The Net power developed in this air-standard Brayton cycle is 43.8MW
b) The rate of heat addition in the combustor is 84.2MW
c) The thermal efficiency of the cycle is 52%
Explanation:
To solve this cycle we need to determinate the enthalpy of each work point of it. If we consider the cycle starts in 1, the air is compressed until 2, is heated until 3 and go throw the turbine until 4.
Considering this:
Now we can calculate the enthalpy of each work point:
h₁=281.4KJ/Kg
h₂=695.41KJ/Kg
h₃=2105KJ/Kg
h₄=957.14KJ/Kg
The net power developed:
The rate of heat:
The thermal efficiency:
Answer:
Heat transfer rate(Q)= 1.197kW
Power output(W)=68.803kW
Answer:
See explaination
Explanation:
A Finite state machines can be synchronous or asynchronous. The operation of asynchronous state machines does not require a clock signal. An Asynchronous state machine is classified basically on their operating mode, such as the fundamental mode, pulse mode or burst mode. An asynchronous state machine can have stable and transient states.
Please kindly refer to attachment for a step by step solution.
Answer:
>>pounds=13.2
>>kilos=pounds/2.2
Explanation:
Using Matlab to write the program, consider at any time when the weight in pounds is 13.2 lb, this variable of weight is created in MATLAB by typing >>pounds=13.2. To convert it from lb to Kg, we simply divide it by 2.2 hence the second command to created is kilos. For this, the output of the program will be 6 Kg.
