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2 years ago

Gravity can be described as

1 answer:

8 0

B. Think about planets, The moon is attracted to the earth and the earth is attracted to the sun. We are attracted to the earth, that's we cant fall off the earth, gravity is pushing on us.

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How high above the ground would a 10 kg object needs to be to have the same GPE as the 30 kg object in the example

Black_prince [1.1K]

Answer:

The 10 kg mass would have to be at a height 3 times that of the 30 kg mass to have the same gravitational potential energy as the 30 kg mass.

Explanation:

Gravitational potential energy, U = mgh where m = mass of object, g = acceleration due to gravity = 9.8 m/s² and h = height of object above the ground.

Now, let U' = gravitational potential energy of 10 kg mass = m'gh' where m' = 10 kg and h' = height of 10 kg mass above the ground.

So, U' = 10gh'

Also, let U" = gravitational potential energy of 30 kg mass = m"gh" where m" = 30 kg and h" = height of 30 kg mass above the ground.

So, U" = 30gh"

Since both object are supposed to have the same potential energy at a given height of the 10 kg mass,

U' = U"

10gh' = 30gh"

h' = 30gh"/10g

h' = 3h"

<u>So, the 10 kg mass would have to be at a height 3 times that of the 30 kg mass to have the same gravitational potential energy as the 30 kg mass.</u>

4 0

2 years ago

An object is moved 29 meters with a force of 289 N. what is the work done

Shtirlitz [24]

Answer:

8381

Explanation:

Workdone=Force x distance

W= 289x 29

W=8381J

8 0

2 years ago

Which of these is the most likely prediction that the meteorologist would make about the weather? There is a possibility of

riadik2000 [5.3K]

Answer:

B. Dust storm

Explanation:

A meteorologist would predict dust storm most likely. Before dust storm the air condition and air pressure reduces in the particular area which indicate towards a dust storm. As pressure of a region reduces the air of the neighboring area try to maintain that pressure and rush towards low pressure area and causes dust storm.

6 0

2 years ago

Suppose the block is released from rest with the spring compressed 5.00 cm. The mass of the block is 1.70 kg and the force const

IRISSAK [1]

First, let's calculate the total mechanical energy when the block is at rest and the spring is compressed 5 cm:

$\begin{gathered} ME=PE+KE\\ \\ ME=\frac{kx^2}{2}+\frac{mv^2}{2}\\ \\ ME=\frac{955\cdot0.05^2}{2}+0\\ \\ ME=1.194\text{ J} \end{gathered}$

Now, let's use this total energy to calculate the velocity when the spring is compressed by 2.5 cm:

$\begin{gathered} ME=PE+KE\\ \\ 1.194=\frac{kx^2}{2}+\frac{mv^2}{2}\\ \\ 2.388=955\cdot0.025^2+1.7v^2\\ \\ 1.7v^2=2.388-0.597\\ \\ 1.7v^2=1.791\\ \\ v^2=\frac{1.791}{1.7}\\ \\ v^2=1.0535\\ \\ v=1.026\text{ m/s} \end{gathered}$

Therefore the speed is 1.026 m/s.

5 0

7 months ago

Determine a formula for the magnitude of the force F exerted on the large block (Mc) so that the mass Ma does not move relative

SVEN [57.7K]

Answer:

The magnitude of the force F is given by

F = ( $M_{a}$ + $M_{b}$ + $M_{c}$ ) *( $M_{b}$ *g/( $\sqrt{M_{a} ^{2}-M_{b} ^{2}}$ ))

Explanation:

Given there are three blocks of masses $M_{a}$ , $M_{b}$ and $M_{c}$ (ref image in attachment)

When all three masses move together at an acceleration a, the force F is given by

F = ( $M_{a}$ + $M_{b}$ + $M_{c}$ ) *a ................(equation 1)

Also it is given that $M_{a}$ does not move with respect to $M_{c}$ , which gives tension T is exerted on pulley by $M_{a}$ only, Hence tension T is

T = $M_{a}$ *a ..........(equation 2)

There is also also tension exerted by $M_{b}$ . There are two components here: horizontal due to acceleration a and vertical component due to gravity g. Thus tension is given by

T = $M_{b}$ $\sqrt{a^{2} +g^{2} }$ ................(equation 3)