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icang [17]
4 years ago
12

Gravity can be described as

Physics
1 answer:
Triss [41]4 years ago
8 0
B. Think about planets, The moon is attracted to the earth and the earth is attracted to the sun. We are attracted to the earth, that's we cant fall off the earth, gravity is pushing on us.
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when a metal sphere is dropped in to a tall cylinder containing liquid its acceleration is g÷2 (gravity over 2) show that : dens
Mamont248 [21]

The density of the metal is twice the density of liquid since acceleration, a is half of accelerating due to gravity, g.

<h3>What is the relationship between acceleration and density?</h3>

For a solid falling through a viscous fluid, the acceleration of the object decreases until it attains terminal velocity.

The acceleration of the body increases with increase in density of the solid.

When density of solid = density of liquid, acceleration a = g

When density of solid = 2 × density of the liquid, acceleration a = g/2.

Therefore, the density of the metal is twice the density of liquid since acceleration, a is half of accelerating due to gravity, g.

Learn more about density and acceleration at: brainly.com/question/1156422

#SPJ1

3 0
2 years ago
The lithosphere consists of _______. select one:
Yanka [14]
The lithosphere is one of the four layers of the earth's interior. The lithosphere is the layer above the mantle of the earth and is the topmost part. Lithosphere includes a part of the mantle and the continental and oceanic crust. 
3 0
3 years ago
When you accelerate in a car and are pushed back into your seat, you are experiencing _______, which is registered by your _____
il63 [147K]

Answer:

E) linear motion; otolith organs 100%

Explanation:

7 0
3 years ago
Two infinite parallel surfaces carry uniform charge densities of 0.20 nC/m2 and -0.60 nC/m2. What is the magnitude of the electr
svlad2 [7]

Answer:

Electric field, E = 45.19 N/C

Explanation:

It is given that,

Surface charge density of first surface, \sigma_1=0.2\ nC/m^2=0.2\times 10^{-9}\ C/m^2

Surface charge density of second surface, \sigma=-0.6\ nC/m^2=-0.6\times 10^{-9}\ C/m^2

The electric field at a point between the two surfaces is given by :

E=\dfrac{\sigma}{2\epsilon_o}

E=\dfrac{\sigma1-\sigma_2}{2\epsilon_o}

E=\dfrac{0.2\times 10^{-9}-(-0.6\times 10^{-9})}{2\times 8.85\times 10^{-12}}

E = 45.19 N/C

So, the magnitude of the electric field at a point between the two surfaces is 45.19 N/C. Hence, this is the required solution.

6 0
3 years ago
What is the measure of how much a material resists the formation of an electric field?
shusha [124]
The answer is c capacitance
5 0
4 years ago
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