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icang [17]
4 years ago
12

Gravity can be described as

Physics
1 answer:
Triss [41]4 years ago
8 0
B. Think about planets, The moon is attracted to the earth and the earth is attracted to the sun. We are attracted to the earth, that's we cant fall off the earth, gravity is pushing on us.
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If a model ship is scaled to the ratio of 1:1,200, what size is the real ship
Ipatiy [6.2K]
The answer I had got was C x
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3 years ago
Balanced- Forces acting on an object are balanced if the ....
choli [55]

Answer:

  • there is an equal and opposite force
  • moving

Explanation:

When balanced forces act on an <em>object at rest</em>, the object will not move. If you push against a wall, the wall pushes back with an equal but opposite force. Neither you nor the wall will move. Forces that cause a change in the motion of an object are unbalanced forces.

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4 years ago
Which type of path do planets follow around the sun?
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A. ellipse...........
4 0
3 years ago
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The index of refraction of silicate flint glass for red light is 1.620 and for violet light is 1.660 . A beam of white light in
chubhunter [2.5K]

Answer:

The angular separation equals 0.35^{o}

Explanation:

We have according to Snell's law

n_{1}sin(\theta _{1})=n_{2}sin(\theta _{2})

\therefore \theta _{2}=sin^{-1}(\frac{n_{1}sin(\theta _{1})}{n_{2}})

Using this equation for both the colors separately we have

\theta _{red}=sin^{-1}(\frac{sin(23.90^{o})}{1.62})\\\\\theta _{red}=14.48^{o}

Similarly for violet light we have

\theta _{violet}=sin^{-1}(\frac{sin(23.90^{o})}{1.660})\\\\\theta _{violet}=14.13^{o}

Thus the angular separation becomes

\Delta \theta =14.48-14.13=0.35^{o}

6 0
4 years ago
A 1500-kg car accelerates from 0 to 30 m/s in 6.0 s. What is the minimum average power delivered by the engine?
nadezda [96]

Answer:

Power, P = 112500 watts

Explanation:

It is given that,

Mass of the car, m = 1500 kg

Initial velocity of the car, u = 0

Final velocity of the car, v = 30 m/s

Time taken, t = 6 s

The minimum average power delivered by the engine is given by :

P = W/t

Where

W = work done

t = time taken

Work done = change in kinetic energy

So, P=\dfrac{\Delta K}{t}=\dfrac{\dfrac{1}{2}m(v^2-u^2)}{t}

P=\dfrac{\dfrac{1}{2}\times 1500\ kg\times (30\ m/s)^2}{6\ s}

P = 112500 watts

So, the minimum average power delivered by the engine is 112500 watts. Hence, this is the required solution.

7 0
3 years ago
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