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galben [10]
3 years ago
11

How much work is done when a barbell is lifted 2.5 meters into the

Physics
1 answer:
ohaa [14]3 years ago
8 0

Answer:

the formula given out a Distance x force you get work done

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Because angular momentum is conserved, an ice-skater who throws her arms out will
ki77a [65]
This is an example of conservation of angular momentum.

The ice skater will rotate more slowly because her arms would be considered the outside torque that is impacting her constant angular momentum.

So, an ice-skater who throws her arms out will rotate more slowly.
8 0
3 years ago
A pole vaulter takes 1.3 seconds to fall from peak height to the landing mat. What is his vertical velocity at contact with the
julia-pushkina [17]

12.75 \frac{m}{s}

Assuming vertical acceleration of 9.81 \frac{m}{s^2}, the speed after x seconds of falling is 9.81x \to 9.81(1.3) = 12.75

6 0
3 years ago
Two thin wires rings each having a radius R are placed at a distance d apart with their axes coinciding. The charges on the two
tigry1 [53]

Answer:

Q/4πε0 [1/R - 1/√R2+d2]

Explanation:

Q/4πε0 [1/R - 1/√R2+d2] is the answer

explanation is attached.

toppr

7 0
2 years ago
the net external force on the 24-kg mower is stated to be 51 N. If the force of friction opposing the motion is 24 N, what force
-Dominant- [34]

Answer:

PART A)

External force will be 75 N

PART B)

distance moved will be 1.125 m

Explanation:

PART A)

Given that net force on the mower is

F_{net} = 51 N

now we also know that friction force due to ground is given as

F_f = 24 N

now we have

F_{net} = F_{ext} - F_f

51 = F_{ext} - 24

F_{ext} = 75 N

so external force will be 75 N

PART B)

deceleration due to friction when external force is removed from it

a = \frac{F_f}{m}

a = \frac{24}{24} = 1 m/s^2

now we can find the distance by kinematics

v_f^2 - v_i^2 = 2 a d

0 - 1.5^2 = 2(-1)d

d = 1.125 m

so the distance moved will be 1.125 m

6 0
3 years ago
Question 3 You see the coordinates 5 E longitude, 10 N latitude. You do not need to look at a map in order to deduce that this l
san4es73 [151]

Answer:

a. Near both the equator and the prime meridian.

Explanation:

The  equator is at 0 degrees latitude and the prime meridian is 0 degrees longitude.

5 0
3 years ago
Read 2 more answers
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