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kakasveta [241]
3 years ago
11

Why does the Zr4+ ion exist?

Chemistry
2 answers:
antiseptic1488 [7]3 years ago
7 0
Zr has atomic number 40 , so it need to lose 4 electrons to gain noble gas configuration of the noble gas Kr
marishachu [46]3 years ago
7 0

Answer:

4 electrons are lost.

Explanation:

Hello,

Zirconium's electron configuration is:

Zr^{40}=1s^22s^22p^63s^23p^64s^23d^{10}4p^65s^24d^2

This allows us to infer that when all the electrons present at both the 5s^2 and the 4d^2 orbitals, 4 electrons are lost (two from 5s^2 and two from 4d^2), allowing the Zr^{4+} species to exist.

Best regards.

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Which of the following will decrease the frequency of collisions?
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Answer:

The question isn't worded properly, but if 1 or 2 are DECREASED, the frequency of collisions of specified molecules will decrease.

Explanation:

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2 years ago
A sample of gas of 752 torr and occupies a volume of 5.12 L. What will the new volume be when the pressure is increased to 1.5 A
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4 years ago
What is the molarity of a solution of sulfuric acid if 49.0 mL of it are neutralized by a titration
vaieri [72.5K]

Answer:

THE MOLARITY OF THE ACID IS 0.232M

Explanation:

Molarity is the number of moles of solute per liter of a solution.

In titration, the molarity of the acid and the molarity of the base are related by this equation:

Ca VA / CbVb = na / nb

Ca = concentration of the acid = ?

Va = volume of the acid = 49 mL

Cb = concentration of the base = 0.333M

Vb = volume of the base = 68.4mL

Na = number of mole of acid = 1

Nb = number of mole of base = 2

Equation for the reaction:

H2SO4 + 2NaOH --------> Na2SO4 + 2H2O

Solving for the molarity of the acid, we have :

Ca = CbVbNa / VaNb

Ca = 0.333M * 68.4mL * 1 / 49mL *2

Ca = 22.7772 * 10^-3 / 98 *10^-3

Ca = 0.232M

The molarity of the acid is therefore 0.232M.

8 0
3 years ago
Read 2 more answers
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