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3 years ago

Why does the Zr4+ ion exist?

Chemistry

2 answers:

antiseptic1488 [7]3 years ago

7 0

Zr has atomic number 40 , so it need to lose 4 electrons to gain noble gas configuration of the noble gas Kr

marishachu [46]3 years ago

7 0

Answer:

4 electrons are lost.

Explanation:

Hello,

Zirconium's electron configuration is:

$Zr^{40}=1s^22s^22p^63s^23p^64s^23d^{10}4p^65s^24d^2$

This allows us to infer that when all the electrons present at both the $5s^2$ and the $4d^2$ orbitals, 4 electrons are lost (two from $5s^2$ and two from $4d^2$ ), allowing the $Zr^{4+}$ species to exist.

Best regards.

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The teacher shows students a pictorial model of an atom. Which element is

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Answer:

C. Fluorine because the model has 9 protons which is represented by the atomic number

Explanation:

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3 years ago

C(S)+O2(g)-->CO2(g)

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Answer: The correct answer is 1.18 g.

Explanation:

We are given a chemical equation:

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1 mole of carbon dioxide gas is produced by 1 mole of carbon

So, 0.0986 moles of carbon dioxide is produced by = $\frac{1}{1}\times 0.0986=0.0986mol$ of carbon.

Now, to calculate the mass of carbon, we use the equation:

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