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kakasveta [241]
2 years ago
11

Why does the Zr4+ ion exist?

Chemistry
2 answers:
antiseptic1488 [7]2 years ago
7 0
Zr has atomic number 40 , so it need to lose 4 electrons to gain noble gas configuration of the noble gas Kr
marishachu [46]2 years ago
7 0

Answer:

4 electrons are lost.

Explanation:

Hello,

Zirconium's electron configuration is:

Zr^{40}=1s^22s^22p^63s^23p^64s^23d^{10}4p^65s^24d^2

This allows us to infer that when all the electrons present at both the 5s^2 and the 4d^2 orbitals, 4 electrons are lost (two from 5s^2 and two from 4d^2), allowing the Zr^{4+} species to exist.

Best regards.

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What is the sequence of coefficients that will balance the following decomposition reaction of dihydrogen monosulfide? H₂S ----&
RUDIKE [14]

8 S

In this case you must start balancing the sulfur to have 8 on each side of the reaction. So:

Answer:

Explanation:

The law of conservation of matter states that since no atom can be created or destroyed in a chemical reaction, the number of atoms that are present in the reagents has to be equal to the number of atoms present in the products.

Then, you must balance the chemical equation. For that, you must first look at the subscripts next to each atom to find the number of atoms in the equation. If the same atom appears in more than one molecule, you must add its amounts.  

The coefficients located in front of each molecule indicate the amount of each molecule for the reaction. This coefficient can be modified to balance the equation, just as you should never alter the subscripts.

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Right side: 2 H and 8 S

In this case you must start balancing the sulfur to have 8 on each side of the reaction. So:

8 H₂S → H₂ + S₈

Now the amount of elements on each side of the equation:

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Right side: 2 H and 8 S

Now you need to start balancing the hydrogen to get the same amount from each side of the reaction. So:

8 H₂S → 8 H₂ + S₈

Now the amount of elements on each side of the equation:

Left side: 16 H and 8  

Right side: 16 H and 8 S

<u><em>The balanced reaction is:</em></u>

<u><em>8 H₂S → 8 H₂ + S₈</em></u>

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