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alekssr [168]
2 years ago
11

5. A football field is about 100 meters long. If it takes a person 20 seconds to run its length, how fast (what speed) were they

running?​
Chemistry
1 answer:
EleoNora [17]2 years ago
7 0

Answer:

Speed, v = 5 m/s

Explanation:

The length of the football field, l = 100 m

the person takes 20 seconds to run its length

v=

t

d

v=

20 s

100 m

v=5 m/s

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Bromine, a liquid at room temperature, has a boiling point of 58°C and a melting point of –7.2°C. Bromine can be classified as a
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Answer:

Pure substance.

Explanation:

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Option b.) Potassium ion, is written correctly.

Explanation:

Hope this helps! :)

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Propane(C3H8) combusts with oxygen gas. If you start with 15 grams of Propane, how many grams of carbon dioxide will be produced
skelet666 [1.2K]
<em>mC₃H₈: 44 g/mol</em>
<em>mCO₂: 44 g/mol</em>
---------------------

C₃H₈ + 5O₂ ----> 3CO₂ + 4H₂O
44g                    (44·3)g


44g C₃H₈ ------ 132g CO₂
15g C₃H₈ ------ X
X = (15×132)/44
<u>X = 45g CO₂
</u>

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4 0
3 years ago
In the background information, it was stated that CaF2 has solubility, at room temperature, of 0.00160 g per 100 g of water. How
____ [38]

Answer:

2.05*10⁻⁵ moles of CF₂ can dissolve in 100 g of water.

12.82 moles of CaF₂ will dissolve in exactly 1.00 L of solution

Explanation:

First, by definition of solubility, in 100 g of water there are 0.0016 g of CaF₂. So, to know how many moles are 0.0016 g, you must know the molar mass of the compound. For that you know:

  • Ca: 40 g/mole
  • F: 19 g/mole

So the molar mass of CaF₂ is:

CaF₂= 40 g/mole + 2*19 g/mole= 78 g/mole

Now you can apply the following rule of three: if there are 78 grams of CaF₂ in 1 mole, in 0.0016 grams of the compound how many moles are there?

moles=\frac{0.0016 grams*1 mole}{78 grams}

moles=2.05*10⁻⁵

<u><em>2.05*10⁻⁵ moles of CF₂ can dissolve in 100 g of water.</em></u>

Now, to answer the following question, you can apply the following rule of three: if by definition of density in 1 mL there is 1 g of CaF₂, in 1000 mL (where 1L = 1000mL) how much mass of the compound is there?

mass of CaF_{2}=\frac{1000 mL*1g}{1mL}

mass of CaF₂= 1000 g

Now you can apply the following rule of three: if there are 78 grams of CaF₂ in 1 mole, in 1000 grams of the compound how many moles are there?

moles=\frac{1000 grams*1 mole}{78 grams}

moles=12.82

<u><em>12.82 moles of CaF₂ will dissolve in exactly 1.00 L of solution</em></u>

5 0
3 years ago
A) How much CO is required for the production of Fe from 1000 tonnes of magnetite (Fe2O4). Assume that the iron ore is 100% pure
Kryger [21]
Its b im pretty sure
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