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2 years ago

What is the relationship between the movement of the atmosphere and surface currents

Physics

1 answer:

maxonik [38]2 years ago

3 0

Answer:

Waves and surface currents are wind-generated. The atmosphere pushes the ocean surface along. But as the ocean moves, heat is redistributed and eventually tossed back into the atmosphere. The exchange of heat influences the pressure field in the atmosphere, which modifies the wind field.

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Two identical cars are parked in the sun on a warm day. One car is black and the other is white. Both cars are parked for three

cestrela7 [59]

Answer:

black will be hotter because black paint absorbs light and white reflects it.

4 0

2 years ago

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The Moon and Earth rotate about their common center of mass, which is located about RcM 4700 km from the center of Earth. (This

erica [24]

To solve this problem it is necessary to apply the concepts related to gravity as an expression of a celestial body, as well as the use of concepts such as centripetal acceleration, angular velocity and period.

PART A) The expression to find the acceleration of the earth due to the gravity of another celestial body as the Moon is given by the equation

$g = \frac{GM}{(d-R_{CM})^2}$

Where,

G = Gravitational Universal Constant

d = Distance

M = Mass

$R_{CM} =$ Radius earth center of mass

PART B) Using the same expression previously defined we can find the acceleration of the moon on the earth like this,

$g = \frac{GM}{(d-R_{CM})^2}$

$g = \frac{(6.67*10^{-11})(7.35*10^{22})}{(3.84*10^8-4700*10^3)^2}$

$g = 3.4*10^{-5}m/s^2$

PART C) Centripetal acceleration can be found throughout the period and angular velocity, that is

$\omega = \frac{2\pi}{T}$

At the same time we have that centripetal acceleration is given as

$a_c = \omega^2 r$

Replacing

$a_c = (\frac{2\pi}{T})^2 r$

$a_c = (\frac{2\pi}{26.3d(\frac{86400s}{1days})})^2 (4700*10^3m)$

$a_c = 3.34*10^{-5}m/s^2$

3 0

3 years ago

What would most likely cause the future acceleration of the expansion of the universe

irga5000 [103]

Answer:

never scared

that might help you

3 0

2 years ago

PLEASE HELP WILL MAKE BRAINIEST (GIVING AWAY 20 POINTS)

Bond [772]

1) The most potential energy is at position A

2) The most kinetic energy is at position C

Explanation:

The gravitational potential energy is the energy possessed by an object due to its position in a gravitational field, and it is given by the equation

$PE=mgh$

where

m is the mass of the object

g is the acceleration of gravity

h is the height of the object relative to the ground

From the equation, we see that the potential energy is directly proportional to the heigth of the object: therefore, the roller coaster in this problem will have the most potential energy at its highest postion, so at position A.

The total mechanical energy of the roller coaster at any point along the track is given by

$E=PE+KE$

where

PE is the potential energy

KE is the kinetic energy

Assuming there is no friction, the mechanical energy E is constant. This means that when PE increases, KE decreases, and when PE increases, KE decreases.

Therefore, the cart will have maximum kinetic energy when the potential energy is at minimum: and since the potential energy is directly proportional to the height of the track, this will occur at the lowest position, so at position C.

Learn more about kinetic and potential energy:

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5 0

3 years ago

What are the main causes of the convention currents in the asthenosphere?

Tju [1.3M]

I think it is c density and temperature

8 0

3 years ago

Read 2 more answers