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2 years ago

ASAP do all will give 25 per person pls will mark brainiest

Physics

1 answer:

neonofarm [45]2 years ago

4 0

Answer:

1) true

2) false

3) false

4) true

5) true

6) true

7) true

8) false

9) true

10) false

i think these are correct if im wrong on a few im sorry. Hope this helps at least a bit. And if i do get some wrong you know just to pick the opposite answer.

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Two taut strings of identical mass and length are stretched with their ends fixed, but the tension in one string is 1.10 times g

ollegr [7]

Answer:

The beat frequency when each string is vibrating at its fundamental frequency is 12.6 Hz

Explanation:

Given;

velocity of wave on the string with lower tension, v₁ = 35.2 m/s

the fundamental frequency of the string, F₁ = 258 Hz

velocity of wave on the string with greater tension;

$v_1 = \sqrt{\frac{T_1}{\mu }$

where;

v₁ is the velocity of wave on the string with lower tension

T₁ is tension on the string

μ is mass per unit length

$v_1 = \sqrt{\frac{T_1}{\mu} } \\\\v_1^2 = \frac{T_1}{\mu} \\\\\mu = \frac{T_1}{v_1^2} \\\\ \frac{T_1}{v_1^2} = \frac{T_2}{v_2^2}\\\\v_2^2 = \frac{T_2v_1^2}{T_1}$

Where;

T₁ lower tension

T₂ greater tension

v₁ velocity of wave in string with lower tension

v₂ velocity of wave in string with greater tension

From the given question;

T₂ = 1.1 T₁

$v_2^2 = \frac{T_2v_1^2}{T_1} \\\\v_2 = \sqrt{\frac{T_2v_1^2}{T_1}} \\\\v_2 = \sqrt{\frac{1.1T_1*(35.2)^2}{T_1}}\\\\v_2 = \sqrt{1.1(35.2)^2} = 36.92 \ m/s$

Fundamental frequency of wave on the string with greater tension;

$f = \frac{v}{2l} \\\\2l = \frac{v}{f} \\\\thus, \frac{v_1}{f_1} =\frac{v_2}{f_2} \\\\f_2 = \frac{f_1v_2}{v_1} \\\\f_2 =\frac{258*36.92}{35.2} \\\\f_2 = 270.6 \ Hz$

Beat frequency = F₂ - F₁

= 270.6 - 258

= 12.6 Hz

Therefore, the beat frequency when each string is vibrating at its fundamental frequency is 12.6 Hz

6 0

3 years ago

A scientist studying the Milky Way galaxy notices a bright light in the sky. What information would she need to prove that the o

Olin [163]

Answer:

Ist and second

Hope it helps

8 0

2 years ago

Charge Q = +4.00 mC is distributed uniformly over the volume of an insulating sphere that has radius R = 5.00 cm. What is the po

sattari [20]

Answer:

3.6 x 10^8 V

Explanation:

Q = 4 m C = 4 x 10^-3 C

r = 5 cm = 0.05 m

The formula for the potential at the surface is

Vs = K Q / r = (9 x 10^9 x 4 x 10^-3) / 0.05 = 7.2 x 10^8 V

The formula for the potential at the centre is

Vc = 3/2 Vs

Vc = 1.5 x 7.2 x 10^8 V = 10.8 x 10^8 V

The difference in potential is

V = Vc - Vs = 10.8 x 10^8 - 7.2 x 10^8 = 3.6 x 10^8 V

8 0

3 years ago

A thermally isolated system consists of a hot piece of aluminum and a cold piece of copper. The aluminum and the copper are in t

Marrrta [24]

Answer:

the amount of heat that gets through both the wires will be same.

Explanation:

By the Fourier's law of conduction we have:

$\dot{Q}=k.A.\frac{dT}{dx}$

where:

$\dot{Q}$ = rate of heat transfer

k = thermal conductivity of the material

A = area of the material

dT = temperature difference across the length dx

According to the question, the system to be analysed is isolated from the surrounding.

Until the thermal equilibrium is established between aluminium and copper wires the amount of heat that gets through both the wires will be same.

But the rate of heat transfer through the aluminium will be greater as it has double the thermal conductivity of copper.

8 0

2 years ago

The transmission of heat requiring the movement of a liquid or a gas is A. transduction. B. convection. C. conduction. D. radiat

madreJ [45]

The correct answer is convection

In liquids and gases, convection is the most prominent method for the transfer of energy or heat. Convection is caused by the movement of the hotter particles to a region of colder particles takes place. This results in making the whole liquid or gas hot or warm.

Example: The water bubbles in boiling water moves from bottom to the top of the pan to cover the colder water present at the top.

This is because of convection.

8 0

2 years ago

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