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3 years ago

Help please I give brainliest

Physics

2 answers:

shutvik [7]3 years ago

7 0

Answer:

can someone help me with physics to

irga5000 [103]3 years ago

5 0

Answer:

equation D=mass/volume

D=m/v

example sample : D=m/v= 250/100 = 2.5 g/cm³

1- D=m/v = 454/2274 = 0.2 g/cm³

2- 1 liter = 1000 cm³

D=m/v=1000/1000= 1 g/cm³

3 - d=m/v

0.6 g/cm³=m / 1.2 cm³

m=0.6*1.2 = 0.72 g

4: a:171/15 = 11.4 g/cm^3 lead

b:148/40 = 3.7 g/cm^3 Aluminum

c:475/250 =1.9 g/cm^3 Bone

d: 680/1000 = 0.68 g/cm^3 Gasoline (lithium)

5: the density of a substance equal to the mass of the substance divide by volume

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Which of the following statements best describes the second law of

Serga [27]

Answer:

Explanation:

Heat flows from hot to cold to lower the temperature of hot areas and increase temperature of cold areas. The end result is that the 2 areas have the same temperature, thus increasing entropy.

7 0

3 years ago

series RC circuit is built with a 15 kΩ resistor and a parallel-plate capacitor with 18-cm-diameter electrodes. A 18 V, 36 kHz s

andre [41]

Answer:

$d=1.84\ mm$

Explanation:

<u>Capacitance</u>

A two parallel-plate capacitor has a capacitance of

$\displaystyle C=\frac{\epsilon_o A}{d}$

where

$\epsilon_o=8.85\cdot 10^{-12}\ F/m$

A = area of the plates = $\pi r^2$

d = separation of the plates

$\displaystyle d=\frac{\epsilon_o A}{C}=\frac{\epsilon_o \pi r^2}{C}$

We need to compute C. We'll use the circuit parameters for that. The reactance of a capacitor is given by

$\displaystyle X_c=\frac{1}{wC}$

where w is the angular frequency

$w=2\pi f=2\pi \cdot 36000=226194.67\ rad/s$

Solving for C

$\displaystyle C=\frac{1}{wX_c}$

The reactance can be found knowing the total impedance of the circuit:

$Z^2=R^2+X_c^2$

Where R is the resistance, $R=15 K\Omega=15000\Omega$ . Solving for Xc

$X_c^2=Z^2-R^2$

The magnitude of the impedance is computed as the ratio of the rms voltage and rms current

$\displaystyle Z=\frac{V}{I}$

The rms current is the peak current Ip divided by $\sqrt{2}$ , thus

$\displaystyle Z=\frac{\sqrt{2}V}{I_p}$

$I_p=0.65\ mA/1000=0.00065\ A$

Now collect formulas

$\displaystyle X_c^2=Z^2-R^2=\left(\frac{\sqrt{2}V}{I_p}\right)^2-R^2$

Or, equivalently

$\displaystyle X_c=\sqrt{\frac{2V^2}{I_p^2}-R^2}$

$\displaystyle X_c=\sqrt{\frac{2\cdot 18^2}{0.00065^2}-15000^2}$

$X_c=36176.34\ \Omega$

The capacitance is now

$\displaystyle C=\frac{1}{226194.67\cdot 36176.34}=1.22\cdot 10^{-10}\ F$

The radius of the plates is

$r=18\ cm/2=9 \ cm = 0.09 \ m$

The separation between the plates is

$\displaystyle d=\frac{8.85\cdot 10^{-12} \cdot \pi\cdot 0.09^2}{1.22\cdot 10^{-10}}$

$d=0.00184\ m$

$\boxed{d=1.84\ mm}$

8 0

2 years ago

Estimate humanity’s current consumption of energy in one day (in Joule).

Alex73 [517]

Based on data from world energy consumption, the estimated humanity’s current consumption of energy in one day is above 208 million joules per day.

<h3>What is energy consumption?</h3>

Energy is the ability to do work. Therefore, energy consumption refers to the amount of energy used to do work.

Humans need energy for various purposes such as;

lighting
heating
operation of machines
feeding, etc.

Due to rapid growth on population as well as technology, the human energy consumption is on the increase.

In 2020, the world primary energy consumption was 71,4 GJ per person for a world population of about 7.7 billion people.

Therefore, the estimated humanity’s current consumption of energy in one day is above 208 million joules per day.

Learn more about energy at: brainly.com/question/6572692

6 0

1 year ago

An upward force of 32.6 N is applied via a string to lift a ball with a mass of 2.8 kg. (a) What is the gravitational force acti

Igoryamba

Answer:

a) Fg = -27.4 N

b) Fnet = 5.2 N

c) a = 1.9 m/s2

Explanation:

There are two forces acting on the ball, one directed upward (assuming this direction as positive, along the y-axis) which is the tension on the string (lifting force), and another aimed downward, which is the attractive force due to gravity.
Applying the Newton's Universal Law of Gravitation to a mass close to the surface of the Earth (in this case the ball), we can take the acceleration due to gravity like a constant, that we call by convention g, equal to -9.8 m/s2.
So, we can write the following expression for Fg:

$F_{g} = m*g = 2.8 kg*(-9.8m/s2) = -27.4 N (1)$

The net force on the ball, will be just the difference between the lifting force (32.6 N) and the force due to gravity, Fg:

$F_{net} = T -F_{g} = 32.6 N - 27.4 N = 5.2 N (2)$

According Newton's 2nd Law, the acceleration caused by a net force on a point mass (we can take the ball as one) is given by the following expression:

$a = \frac{F_{net} }{m} = \frac{5.2N}{2.8kg} = 1.9 m/s2 (3)$

3 0

2 years ago

What single property was the most important in jesseca's material

jek_recluse [69]

Answer:

Jesseca wanted to create a material that reflected most of the light that fell on it.

Explanation: The Graphite was the material in the passage that had reflected most of the light.

6 0

3 years ago