Question

Now create a separate function called sphereVolume that determines the volume of a sphere with a given radius and prints the result to the screen. Specifications:
a. Your function MUST be named sphereVolume
b. Your function should have one input argument: a floating point parameter representing the radius - as a double
c. Your function should not return anything.
d. Your function should print the calculated volume.
e. The output format should resemble that of the previous problem. For a radius of 5, the function should print:

Answer 1

Answer:

The question is not complete. the complete question is shown below.

Now create a separate function called sphereVolume that determines the volume of a sphere with a given radius and prints the result to the screen. Specifications:

a. Your function MUST be named sphereVolume

b. Your function should have one input argument: a floating point parameter representing the radius - as a double

c. Your function should not return anything.

d. Your function should print the calculated volume.

e. The output format should resemble that of the previous problem. For a radius of 5, the function should print:

Volume: 523.99

Explanation:

Answer 2

complete question:

Now create a separate function called sphereVolume that determines the volume of a sphere with a given radius and prints the result to the screen. Specifications:

a. Your function MUST be named sphereVolume

b. Your function should have one input argument: a floating point parameter representing the radius - as a double

c. Your function should not return anything.

d. Your function should print the calculated volume.

e. The output format should resemble that of the previous problem. For a radius of 5, For example: Test Result sphereVolume(5); volume: 523.599

Answer:

import math

def sphereVolume(r):

          # where r = radius of the sphere

             volume = 4/3 * math.pi * r**3

             print(round(volume, 3))

sphereVolume(5)

Explanation:

The code is written in python .

def sphereVolume(r):

This line of code defines the function as instructed as sphereVolume.

# where r = radius of the sphere

This is just a line of comment to explain that the argument r is the radius

volume = 4/3 * math.pi * r**3

The volume of a sphere is 4$\pi$r³. so the code define the formula of a volume of a sphere and stored it in a variable called volume.

print(round(volume, 3))

The code displays the answer of a volume of a sphere when passing  the radius  of a sphere as the argument . The volume of the sphere is rounded to 3 decimal place using the function round.

sphereVolume(5)

This code calls the function with the argument which is the radius.