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3 years ago

5. Identify the pros and cons of manufactured siding.

1 answer:

5 0

Aluminum
Aluminum siding is out of date and really has no advantages in today’s market. It dents, it’s difficult to keep clean, and it’s hard to update it once it’s installed. Aluminum siding is not recommended, and most professional contractors won’t even install it.

Vinyl
Today’s mainstream siding material is vinyl. It is the most economical type of siding, coming in at $4 to $5 per square foot.

Available in a wide variety of colors, vinyl siding not only protects your home, it can make a statement. You can choose from whites, ivories, grays, browns, reds, greens and even blues — there’s a color for everyone.

In addition, vinyl is a complete self-flushing water-exclusion system. It is made to be water repellent and durable in any kind of weather. Its lightweight footprint makes it easy to install, which minimizes expenses.

Vinyl is low-maintenance and requires only periodic cleaning with a power washer every few years – more if you want it to really shine.

Premium vinyl
A step up from regular vinyl, premium vinyl gives you a more wood-like appearance. It’s usually a thicker vinyl that looks more rigid because it has no oil canning, as lighter vinyl does.

The upgrade to premium gives you more strength and longer lifespan. Many premium vinyl sidings also have integrated insulation or r-values (insulation grade) of 5 to 6.

Premium vinyl cost is generally higher than vinyl, at around $7 to 8 per square foot. Premium vinyl also comes in a rainbow of colors for customization and personalization

Natural wood
Wood siding provides a more rustic look for your home, with a more customized result.

The siding can be in long horizontal pieces or it can be shaped to suit your individual design needs. That’s the beauty of wood. You may want the look of clapboard – overlapping pieces of wood installed horizontally – or shingles – smaller pieces of wood overlapping like a shingled roof. Wood siding is a good choice for this façade.

Fiber cement siding
Finally, you may hear about fiber cement siding. Today’s version is a combination of wood pulp, cement, clay and sand. It can be made to look like wood siding, and it is installed and wears much like wood siding.

This is different from the fiber cement siding that was used in homes built prior to the late 1980s. Those older sidings contain asbestos, and any work with them should be done by a specialized asbestos-removal professional. Today’s fiber cement siding is safer and longer-lasting, if you’re willing to pay the price.

Fiber cement siding can be ordered pre-colored, eliminating the need to paint the siding. If you prefer to paint it, that is still an option, because the material does accept paint rather easily. Fiber cement siding requires a periodic recaulk of butt joints at trim terminations, which is a little more maintenance than a vinyl siding.

When to replace siding
When should you replace your siding? It should be replaced if it has any kind of water damage, mold or rotting. If it hasn’t been properly maintained, it might be time for new siding. And, of course, if you simply want a new look, new siding can be a side show for the neighborhood.

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Introduction to gear and gear ratios: If you have two gears of the same size does the output speed increase, decrease, or remain

creativ13 [48]

Answer:

remain the same constant

Explanation:

if a small gear is making 5 rpm turning a big gear thats making 1 rpm the bug gear is making lots of torque but if its going the opposite way its much harder to turn the big gear 1 rpm just to make the little gear do 5 rpm and it makes way less torque if thre both the same size there ging to stay the same speed

4 0

3 years ago

A piston/cylinder contains 1.5 kg of water at 200 kPa, 150°C. It is now heated by a process in which pressure is linearly relate

Fofino [41]

Answer:

final volume V2 = 0.71136 m³

work done in process W = -291.24 kJ

heat transfer Q = 164 kJ

Explanation:

given data

mass = 1.5 kg

pressure p1 = 200 kPa

temperature t1 = 150°C

final pressure p2 = 600 kPa

final temperature t2 = 350°C

solution

we will use here superheated water table that is

for pressure 200 kPa and 150°C temperature

v1 = 0.95964 m³/kg

u1 = 2576.87 kJ/kg

and

for pressure 600 kPa and 350°C temperature

v2 = 0.47424 m³/kg

u2 = 2881.12 kJ/kg

so v1 is express as

V1 = v1 × m ............................1

V1 = 0.95964 × 1.5

V1 = 1.43946 m³

and

V2 = v2 × m ............................2

V2 = 0.47424 × 1.5

final volume V2 = 0.71136 m³

and

W = P(avg) × dV .............................3

P(avg) = $\frac{p1+p2}{2}$ = $\frac{200+600}{2}$ = 400 × 10³

put here value

W = 400 × 10³ × (0.71136 - 1.43946 )

work done in process W = -291.24 kJ

and

heat transfer is

Q = m × (u2 - u1) + W .............................4

Q = 1.5 × (2881.12 - 2576.87) + 292.24

heat transfer Q = 164 kJ

7 0

3 years ago

How long should the shafts remain in the furnace to achieve a desired centerline temperature of 800K? 2) Determine the temperatu

Phantasy [73]

Answer:

Check the explanation

Explanation:

Kindly check the attached image below to see the step by step explanation to the question above.

6 0

3 years ago

For a steel alloy it has been determined that a carburizing heat treatment of 11.3 h duration will raise the carbon concentratio

diamong [38]

This question is incomplete, the complete question is;

For a steel alloy it has been determined that a carburizing heat treatment of 11.3 h duration at Temperature T1 will raise the carbon concentration to 0.44 wt% at a point 1.8 mm from the surface. A separate experiment is performed at T2 that doubles the diffusion coefficient for carbon in steel.

Estimate the time necessary to achieve the same concentration at a 4.9 mm position for an identical steel and at the same carburizing temperature T2.

Answer:

the required time to achieve the same concentration at a 4.9 is 83.733 hrs

Explanation:

Given the data in the question;

treatment time t₁ = 11.3 hours

Carbon concentration = 0.444 wt%

thickness at surface x₁ = 1.8 mm = 0.0018 m

thickness at identical steel x₂ = 4.9 mm = 0.0049 m

Now, Using Fick's second law inform of diffusion

$x^2$ / Dt = constant

where D is constant

then

$x^2$ / t = constant

$x^2_1$ / t₁ = $x^2_2$ / t₂

$x^2_1$ t₂ = t₁ $x^2_2$

t₂ = t₁ $x^2_2$ / $x^2_1$

t₂ = ( $x^2_2$ / $x^2_1$ )t₁

t₂ = $($ $x_2$ / $x_1$ $)^2$ × t₁

so we substitute

t₂ = $($ 0.0049 / 0.0018 $)^2$ × 11.3 hrs

t₂ = 7.41 × 11.3 hrs

t₂ = 83.733 hrs

Therefore, the required time to achieve the same concentration at a 4.9 is 83.733 hrs

8 0

3 years ago

Technician A ay that acid rain doe the mot harm when it firt fall on a finih. Technician B ay that hard water potting i uually j

Tamiku [17]

Technician B is right say that hard water potting i usually jut a Surface problem that can be wahed off.

What do you mean by Hard water?

The amount of dissolved calcium and magnesium in the water determines its hardness. Calcium and magnesium are the main dissolved minerals in hard water. The last time you washed your hands, you might have actually felt the effects of hard water.

What do you mean by acid rain?

Any type of precipitation that contains acidic elements, such as sulfuric or nitric acid, that falls to the ground from the atmosphere in wet or dry forms is referred to as acid rain, also known as acid deposition. Rain, snow, fog, hail, and even acidic dust can fall under this category.

Some plants are sensitive to excessive moisture around their root zone, so it may be necessary to increase drainage when growing plants in pots. Additionally, standing water at the bottom of the pot can cause root rot.

Many university agriculture extension agencies have thoroughly debunked the old garden myth that adding rocks to the bottom of a pot will increase drainage.

Learn more about hard water click here:

brainly.com/question/28178305

#SPJ4

6 0

1 year ago