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Luda [366]
3 years ago
11

Two points, point A and point B, are situated above a current-carrying wire. Point B is located at a distance R from the wire, w

hich is twice as far from the wire as point A. By what factor is the magnetic field at point A larger or smaller than the magnetic field at point B?
Physics
1 answer:
padilas [110]3 years ago
7 0

Explanation:

It is given that, there are two points situated above a current-carrying wire. Point B is located at a distance R from the wire, which is twice as far from the wire as point A such that,

r_B=R

And r_A=R/2

We know that the magnetic field at a distance R is inversely proportional to the distance from wire as :

B=\dfrac{\mu_o}{2\pi}\dfrac{I}{r}

B_A\propto\dfrac{1}{(R/2)}

B_B\propto\dfrac{1}{(R)}

\dfrac{B_A}{B_B}=\dfrac{1/(R/2)}{1/R}

\dfrac{B_A}{B_B}=\dfrac{2}{1}

B_A=2B_B

So, the magnetic field at point A larger than the magnetic field at point B by a factor of 2. Hence, this is the required solution.

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