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vivado [14]
3 years ago
7

Thermal expansion results in

Physics
2 answers:
PIT_PIT [208]3 years ago
4 0
Thermal expansion<span> is the tendency of matter to change in shape, area, and volume in response to a change in temperature, through </span>heat<span> transfer. Temperature is a monotonic function of the average molecular kinetic energy of a substance. When a substance is heated, the kinetic energy of its molecules increases.so this can result in.......heat</span>
lorasvet [3.4K]3 years ago
3 0
The tendency of matter to change in shape, area, and volume in response
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Most people would consider a comfortable room temperature to be
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B

A  is extremly hot

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3 years ago
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A uniformly charged sphere has a potential on its surface of 450 V. At a radial distance of 7.2 m from this surface, the potenti
Yakvenalex [24]

Answer:

The radius of the sphere is 3.6 m.

Explanation:

Given that,

Potential of first sphere = 450 V

Radial distance = 7.2 m

If the potential of sphere =150 V

We need to calculate the radius

Using formula for potential

For 450 V

V=\dfrac{kQ}{r}

450=\dfrac{kQ}{r}....(I)

For 150 V

150=\dfrac{kQ}{r+7.2}....(II)

Divided equation (I) by equation (II)

\dfrac{450}{150}=\dfrac{\dfrac{kQ}{r}}{\dfrac{kQ}{r+7.2}}

3=\dfrac{(r+7.2)}{r}

3r=r+7.2

r=\dfrac{7.2}{2}

r=3.6\ m

Hence, The radius of the sphere is 3.6 m.

3 0
3 years ago
a car with a mass of 2,000 kilograms is moving around a circular curve at a uniform velocity of 25 meters per second. the curve
Ber [7]
Fc=mv^2/r so we get 

2000kg*(25m/s)^2/(80m)= 15625N of force 

hope this helps! Thank You!!

4 0
3 years ago
Define 1 joule work ?​
Nina [5.8K]

Explanation:

Force is applied to lift a body against the force of gravity. Example: If an object is lifted to a certain height (h)

4 0
2 years ago
The coulombic force between two ions is reduced to ______ of its original strength when the distance between them is quadrupled.
gayaneshka [121]

Answer:

<h3>1/16</h3>

Explanation:

According to the coulombs law, the force existing vetween the ions is expressed as;

F = kQq/r² .... 1

Q and q are the ions

r is the distance between the ions

If the distance between the ion is quadrupled, then;

F2 =  kQq/(4r)²

F2 =  kQq/16r² ... 2

Divide equation 2 by 1;

F2/F = kQq/16r² ÷ kQq/r²

F2/F = kQq/16r² × r²/kQq

F2/F = 1/16

F2 = 1/16 F

Therefore the coulombic force between two ions is reduced to<u> 1/16 </u>of its original strength when the distance between them is quadrupled.

6 0
3 years ago
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