Answer: set up a reminder so you won't forget also try clearing your schedule so you can have more time
Answer:
30.22 hours
Explanation:
Given data:
A= l² = (2 x
)² = 4 x
m²
Length 'L' = 5m
current '
' = 2 A
density of free electrons 'n'= 8.5 x
/m³
Current Density 'J' =
/ A
J= 2/4 x
J= 5 x
A/m²
We can determine the time required for an electron to travel the length of the wire by
T= L/ Vd
Where,
L is length and Vd is drift velocity.
Vd can be defined by J/ n|q|
where,
n is the charge-carrier number density
|q| is is the charge carried by each charge carrier
=>1.6 x
C
T= L/ Vd
Therefore,
T= L . n|q| / J
T= (4 x 8.5 x
x |1.6 x
|)/5 x
T= 108800 seconds =>1813.33 minutes
Converting minute into hours:
T= 30.22 hours
Thus, time that is required for an electron to travel the length of the wire is 30.22 hours
Yes, because cell phones use scientific structure to build.
Using the two kinematic equations that can be used for this problem are:
Vf = Vi + at and d=Vit +(1/2)*at^2
Since Vi (initial velocity) = 0
The equations can further be simplified where a is the acceleration, t is the time, Vf is the final velocity which is 70 miles per hour and d is 6 miles
Vf = at
70 = at
a = 70/t---equation 1
d=(1/2)*a*(t^2)
6 = (1/2)*a*(t^2) ---equation 2
Substituting equation 1 to equation 2.
6= (1/2)*(70/t)*(t^2)
6= 35t
t= 0.17142 hours or 10.28571 mins or 617.14 sec
Four squares are in a 2×2 grid.