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horrorfan [7]
3 years ago
9

A 12 kg barrel is pulled up by a rope. The barrel accelerates at 1.2 m/s2. Find the force exerted by the rope. Show all your wor

k.
Physics
1 answer:
IgorLugansk [536]3 years ago
3 0

Answer:

F = 132N

Explanation:

Let the pulling force be F

Given the mass of the barrel is 12 Kg and The acceleration is 1.2 m/sec^2

We know that Net Force = mass\times acceleration

Now net force = F - mg

F - mg = ma

F = mg + ma

F = m(a+g) = 12\times (1.2 +9.8)=132N  

Note that there will be a downward force acting on the body which is equal to mg

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0.09 x10^-10m

Explanation:

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A car is moving at a initial velocity of 20 meters per second accelerates at a rate of 1.5 meters per second squared for 4 secon
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3 years ago
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2 years ago
A kayakeris paddling 2.50 m/s at an angle of 45° (northeast) and the current is moving 1.25 m/s at an angle of 315° (southeast).
PIT_PIT [208]

The kayaker has velocity vector

<em>v</em> = (2.50 m/s) (cos(45º) <em>i</em> + sin(45º) <em>j</em> )

<em>v</em> ≈ (1.77 m/s) (<em>i</em> + <em>j</em> )

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<em>w</em> = (1.25 m/s) (cos(315º) <em>i</em> + sin(315º) <em>j</em> )

<em>w</em> ≈ (0.884 m/s) (<em>i</em> - <em>j</em> )

The kayaker's total velocity is the sum of these:

<em>v</em> + <em>w</em> ≈ (2.65 m/s) <em>i</em> + (0.884 m/s) <em>j</em>

That is, the kayaker has a velocity of about ||<em>v</em> + <em>w</em>|| ≈ 2.80 m/s in a direction <em>θ</em> such that

tan(<em>θ</em>) = (0.884 m/s) / (2.65 m/s)   →   <em>θ</em> ≈ 18.4º

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5 0
3 years ago
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