First we will calculate free energy change:
ΔG₀ = ΔH₀ - (T * ΔS₀)
= - 793 kJ - (298 * - 0.319 kJ/K) = - 698 kJ
We know the relation between free energy change and cell potential is:
ΔG₀ = - n F E⁰ where
F = Faraday's constant = 96485 C/mol
n = 2 (given by equation that the electrons involved is 2)
ΔG₀ = - 2 x 96485 x E⁰
- 698 kJ = - 2 x 96485 x E⁰
E⁰ = (698 x 1000) / (2 x 96485) = 3.62 volts
your answer is c. two atoms of oxygen.
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Answer: any answer choices
Explanation:
First of all the ethylamine is base so will be react with water to take the proton from the water (H⁺) , because water is amphoteric will react with bases as acid and acids as a base, so the water in this case will react as an acid and will gives the proton to the base.
In the picture you may see the chemical equation and the structure of the products.