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boyakko [2]
2 years ago
10

The use of evaporation and condensation to separate the partsof a mixture is called _____

Chemistry
1 answer:
Keith_Richards [23]2 years ago
5 0

Answer: Evaporation Condensation is used to seperate the parts of a mixture

Explanation: This is because it is the first order of the distilation process

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You need to make 10 mL of 2 mg/ml solution of protein and you have 25 mg/mL solution. How much protein solution and water do you
meriva

Answer:

0.8 mL of protein solution, 9.2 mL of water

Explanation:

The dilution equation can be used to relate the concentration C₁ and volume V₁ of the stock/undiluted solution to the concentration C₂ and volume V₂ of the diluted solution:

C₁V₁ = C₂V₂

We would like to calculate the value for V₁, the volume of the inital solution that we need to dilute to make the required solution.

V₁ = (C₂V₂) / C₁ = (2mg/mL x 10mL) / (25 mg/mL) = 0.8 mL

Thus, a volume of 0.8 mL of protein solution should be diluted with enough water to bring the total volume to 10 mL. The amount of water needed is:

(10 mL - 0.8 mL) = 9.2 mL

6 0
3 years ago
Which of the following elements is the most reactive?
Maksim231197 [3]
<span>the following element that is most reactive </span>would be  Fluorine
4 0
3 years ago
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Rick has taken a loan of $3,200 from the bank to buy new appliances. His first loan payment is due at the end of this month. He
marysya [2.9K]

Answer:

140

Explanation:

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3 years ago
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What is the density of an<br> object that has a mass of<br> 120 g and volume of 5 ml?
Viktor [21]

The density of an  object ρ = 24 g/ml

<h3>Further explanation</h3>

Given

mass of an object = 120 g

volume = 5 ml

Required

The density

Solution

Density is a quantity derived from the mass and volume  

Density is the ratio of mass per unit volume  

Density formula:  

\large {\boxed {\bold {\rho ~ = ~ \frac {m} {V}}}}

ρ = density  

m = mass  

v = volume  

Input the value :

ρ = 120 g : 5 ml

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3 years ago
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ln [A] = -kt + ln [A]_o, where,

k is the rate constant
t is the time of the reaction
[A] is the concentration of the species at the given time
[A]_o is the initial concentration of the species

For this problem, we simply substitute the known values to the equation as in:

ln[A] = -(6.7 x 10⁻⁴ s⁻¹)(644 s) + ln (1.33 M) 

We then determine that the final concentration of cyclopropane after 644 s is 0.86 M.
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3 years ago
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