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boyakko [2]
2 years ago
10

The use of evaporation and condensation to separate the partsof a mixture is called _____

Chemistry
1 answer:
Keith_Richards [23]2 years ago
5 0

Answer: Evaporation Condensation is used to seperate the parts of a mixture

Explanation: This is because it is the first order of the distilation process

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What is the specific heat of a substance if 25 grams rises in temperature from 10 degrees Celsius to 25 degrees with the additio
Marina86 [1]

Answer:

0.75 cal/g°c

Explanation:

for specific heat we have formula:

Amount of heat absorbed or released = mass x specific heat of a substance x change in temperature.

ΔQ=m x c x ΔT

where c= specific heat

m= mass of a substance

ΔT = total temperature

ΔQ = Amount of heat

so for specific heat,

c= ΔQ/mxΔT

c= 280/25x (25-10)

c= 280/375

c= 0.75 cal/g°c

4 0
3 years ago
True or False: Electrons in each lower level are filled before electrons fill
ale4655 [162]

the answer is 1....true

5 0
3 years ago
How is percipation related to high and low pressure
Mila [183]
Typical air flow i believe hope i helped

6 0
3 years ago
What would you need to do to calculate the molarity of 10g of NaCl in 2kg of water?
Artist 52 [7]

Answer:

B) we will convert the 10 g of NaCl into moles.

Explanation:

Molarity is used to describe the concentration of solution. It tells how many moles are dissolve in per litter of solution.

Formula:

Molarity = number of moles of solute / L of solution

we will convert the 10 g of NaCl into moles.

Number of moles of NaCl:

Number of moles = mass/molar mass

Number of moles = 10 g/ 58.44 gmol

Number of moles = 0.17 mol

1 Kg = 1 L

Molarity = 0.17 mol / 2 L

Molarity = 0.085 mol/L

Molarity = 0.085 M

6 0
3 years ago
Read 2 more answers
What is the hydrogen ion and hydroxide ion concentration for a pOH of 3.557? Is the solution an acid or a base?​
UkoKoshka [18]

Answer:

Hydrogen ion concentration is 2.773E-4Mole per DM3

Hydroxide ion concentration is 4.093E-11

It is an acid

Explanation:

PH(H3O)=-LogH3O

PH=3.557

H3O=antilog of -3.557

antilog of -3.557=antilog (0.443 -4)

antilog0.443 ×antilog -4=2.773E-4mole per DM3.

(H3O)(OH)=10^-14

H30=2.773×10^-14

OH= 1.00E-14/2.773E-4

=4.093E-11

it is an acid since the concentration of hydrogen ion is more than the hydroxide ion

4 0
3 years ago
Read 2 more answers
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