Draw the curved arrow mechanism for the formation of an acetal from acidic methanol and 4-methylpentan-2-one in the fewest steps
. When given the choice, draw the arrows that lead to the resonance structures with full octets around each atom other than hydrogen. Do not show any inorganic byproducts or counterions. Reagents needed for each step are provided in the boxes.
1 answer:
Answer:
See explanation below
Explanation:
This reaction is known as Ketone hydrolisis in acid medium. This involves the formation of an hemi cetal, and then, the acetal. This is often used to convert ketones or aldehydes in ethers.
The first step involves the reaction with the acid. The carbonile reacts with the acid and forms an alcohol there. The next step is the reaction of the alcohol, in this case, the methanol to form the hemi cetal. Then in the third step, we repeat the first step, using acid to turn the OH group into a great leaving group such water. Then the water leaves the molecule, leaving the space wide open in the next step for methanol, and the acetal is formed.
See picture for the curved arrow mechanism
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<u>Answer:</u> The mass of required is 14.37 g
<u>Explanation:</u>
Molarity is calculated by using the equation:
......(1)
We are given:
Molarity of iron (II) sulfate = 1 M
Volume of solution = 200 mL = 0.200 L (Conversion factor: 1 L = 1000 mL)
Putting values in equation 1, we get:
The chemical equation for the reaction of FeO with sulfuric acid follows:
By stoichiometry of the reaction:
If 1 mole of iron (II) sulfate is produced by 1 mole of FeO
So, 0.200 moles of iron (II) sulfate will produce = of FeO
The number of moles is defined as the ratio of the mass of a substance to its molar mass. The equation used is:
We know, molar mass of = 71.84 g/mol
Putting values in above equation, we get:
Hence, the mass of required is 14.37 g
Answer:
Rate = 116m⁻¹s⁻¹[lactose][H]⁺
Explanation:
the formula for rate of reaction is given as
Rate = k[lactose]∧α[H]⁺∧β
we solve for the value of α and β
([lactose]₁/[lactose]₂)∧α
α =
when we divide this equation
α =
α = 1
we find β
R₁/R₂ = 0.01/0.02(0.001/0.001)∧β
0.00116/0.00232 = 0.5(1)∧β
β = 1
Rate = k[lactose]∧α[H]⁺∧β
we have to find the value for k
k = 0.00116/0.01(0.001)
k = 0.00116/0.00001
= 116m⁻¹s⁻¹
<u>Rate = 116m⁻¹s⁻¹[lactose][H]⁺</u>
