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3 years ago

What happens when you push a spring? How is this different than pulling it? (Hooke’s Law)

2 answers:

7 0

A spring is an object that can be deformed by a force and then return to its original shape after the force is removed.Springs come in a huge variety of different forms, but the simple metal coil spring is probably the most familiar. Springs are an essential part of almost all moderately complex mechanical devices; from ball-point pens to racing car engines.

Furkat [3]3 years ago

4 0

When you push a spring you are putting force on it, or rather forcing the spring onto its self. This is different than pulling the spring because when you push it and let go it will spring but if you pull it its would not move as far as it would if you push it. Pulling the spring would most likely deform the spring will pushing it would cause it to spring back into place.

<u>Hooke's law states that the force that extends or compresses a spring by some distance scales linearly with respect to that distance.</u>

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A small boat coasts at constant speed under a bridge. A heavy sack of sand is dropped from the bridge onto the boat. The speed o

Tju [1.3M]

Answer:

d. decreases

Explanation:

The law of conservation of momentum tells us that the sum of momenta before the collision is equal to the sum of momenta after the collision. The bag has no momentum as it falls onto the boat because its velocity is zero in the horizontal direction. But after it hits the boat, it's momentum increases while the momentum of the system remains the same. That means a component of the system must decrease somewhere else. And that component is the velocity, not the mass, of the boat.

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3 years ago

When the speed of the bottle is 2 m/s, the KE is kg m2/s2. When the speed of the bottle is 3 m/s, the KE is kg m2/s2. When the s

d1i1m1o1n [39]

mass of the bottle in each case is M = 0.250 kg

now as per given speeds we can use the formula of kinetic energy to find it

1) when speed is 2 m/s

kinetic energy is given as

$K = \frac{1}{2}mv^2$

$K = \frac{1}{2}(0.250)(2)^2 = 0.5 J$

2) when speed is 3 m/s

kinetic energy is given as

$K = \frac{1}{2}mv^2$

$K = \frac{1}{2}(0.250)(3)^2 = 1.125 J$

3) when speed is 4 m/s

kinetic energy is given as

$K = \frac{1}{2}mv^2$

$K = \frac{1}{2}(0.250)(4)^2 = 2 J$

4) when speed is 5 m/s

kinetic energy is given as

$K = \frac{1}{2}mv^2$

$K = \frac{1}{2}(0.250)(5)^2 = 3.125 J$

5) when speed is 6 m/s

kinetic energy is given as

$K = \frac{1}{2}mv^2$

$K = \frac{1}{2}(0.250)(6)^2 = 4.5 J$

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3 years ago

Read 2 more answers

What type of specialized training is necessary to learn the skills needed to work in this career field

Nonamiya [84]

Answer:

DONTKNOW NEED CAREER FILD FIRST TO ANWSER

Explanation:

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3 years ago

BRAINLIEST

In-s [12.5K]

Answer:

Explanation:

1) acceleration is the change in velocity of a body with respect to time.

acceleration = velocity/time

Given

velocity = 139m/s

time = 20secs

acceleration = 139/20

acceleration = 6.95m/s²

Hence its average acceleration during the first 20 seconds of the launch is 6.95m/s²

2) Speed is the rate of change of distance with respect to time.

average speed = distance/time

Time = distance/speed

Time = 100/7823

Time = 0.013s

3) Using the equation of motion v² = u²+2as

v² = 0²+2(15)(60)

v² = 30*60

v² =1800

v = √1800

v = 42.43m/s

7 0

3 years ago

The potential at points a and b are: va = -2 v and vb = 6 v. when a 5 c charge is moved from a to b, the change in potential ene

zhenek [66]

The change in potential energy of this system is = 40 J.

<h3>What is the potential difference?</h3>

The potential difference, often known as voltage, is equal to the amount of current times the resistance. One Joule, or one Volt, of energy is required for one Coulomb of charge to flow from one place in a circuit to another.

<h3>What is the formula for potential difference?</h3>

V=Uq The change in potential energy of a charge q transported from point A to point B, divided by the charge, is what is used to determine the electric potential difference between points A and B, or VBVA. The joules per coulomb unit of potential difference is called the volt (V).

This system's potential energy changed by 40 J.

Energy = charge * potential difference

=> Energy = (8v)*5

=> Energy = 40 J

The change in potential energy of this system is = 40 J.

To know more about Potential Difference visit:

brainly.com/question/12198573

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1 year ago