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AleksandrR [38]
3 years ago
13

Which type of bonding is present when valence electrons move within the sample?

Chemistry
2 answers:
notsponge [240]3 years ago
3 0
That is metalic bonding.

That bonding is formed between the delocalized valence electrons in a metal and the ions of the metal (which are positive).

The delocalized electrons can move freely among the set of orbitals of neighbors atoms which is a characteristic of the metals.
Flura [38]3 years ago
3 0

Answer is: metallic bonding.

1. Metallic bond is a type of chemical bond.  

2. Metallic bond is formed between electrons and positively charged metal ions.  

3. Metallic radius is defined as one-half of the distance between the two adjacent metal ions.  

4. Metallic bond increace electrical and thermal conductivity.  

5. Metals conduct heat, because when free moving electrons gain energy (heat) they vibrate more quickly and can move around.  

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Which of the statements below about buoyancy is true?
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Buoyancy is a force that acts on objects that are placed in a fluid is the correct answer
Let me know if I agit it!
3 0
4 years ago
an alpha particle is identical to a). a neutron b) a helium nucleus c) an electron d) a hydrogen nucleus​
ElenaW [278]

Alpha particles, also called alpha ray or alpha radiation, consist of two protons and two neutrons bound together into a particle identical to a <u>helium-4 nucleus. </u>They are generally produced in the process of alpha decay, but may also be produced in other ways.

Composition: 2 protons, 2 neutrons

Mass: 6.644657230(82)×10−27 kg; 4.0015061...

Electric charge: +2 e

Symbol: α, α2+, He2+

3 0
3 years ago
Read 2 more answers
How many moles of NaOH must be dissolved in 1.00 L of water to make NaOH (aq) with a pH of 12.2?
adelina 88 [10]

Answer:

1.58 102 mol

Explanation:

I just looked it up on Quizlet.

6 0
3 years ago
Methane, a component in natural gas, can be used as a fuel in combustion reactions. What is the value for ΔGnon (in kJ) for the
Oksanka [162]

<u>Answer:</u> The \Delta G for the reaction is -806.86 kJ

<u>Explanation:</u>

We are given:

\Delta H^o_{rxn}=-803kJ=-803000J      (Conversion factor:  1 kJ = 1000)

\Delta S^o_{rxn}=-4.05J/K

Temperature of the reaction = 293 K

To calculate the standard Gibbs's free energy of the reaction, we use the equation:

\Delta G^o_{rxn}=\Delat H^o_{rxn}-T\Delta S^o_{rxn}

Putting values in above equation, we get:

\Delta G^o_{rxn}=-803000J-[(293K)\times (-4.05J/K)]=-801813.35J

For the given chemical equation:

CH_4(g)+2O_2(g)\rightleftharpoons CO_2(g)+2H_2O(g)

The expression for K_c is given as:

K_{c}=\frac{[H_2O]^2[CO_2]}{[CH_4][O_2]^2}

We are given:

[H_2O]=6.41M

[CO_2]=3.83M

[CH_4]=14.51M

[O_2]=9.27M

Putting values in above equation, we get:

K_c=\frac{(6.41)^2\times 3.83}{14.51\times (9.27)^2}

K_c=0.126

To calculate the Gibbs free energy of the reaction, we use the equation:

\Delta G=\Delta G^o+RT\ln K_c

where,

\Delta G = Gibbs' free energy of the reaction = ?

\Delta G^o = Standard gibbs' free energy change of the reaction = -801813.35 J

R = Gas constant = 8.314J/K mol

T = Temperature = 293 K

K_c = equilibrium constant in terms of concentration = 0.126

Putting values in above equation, we get:

\Delta G=-801813.35J+(8.314J/K.mol\times 293K\times \ln(0.126))

\Delta G=-806859.46J=-806.86kJ

Hence, the \Delta G for the reaction is -806.86 kJ

8 0
3 years ago
Pleaseee I need help and it is urgent
ZanzabumX [31]

Answer:

1)4180j

2)15000kj

Explanation:

1) E=100*(30-20)*4.18=4180j\\2)Q=.5*30*1000=15000kj

6 0
4 years ago
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