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Maru [420]
3 years ago
14

I have 3 questions i'm curious about *SCIENCE*

Chemistry
1 answer:
jekas [21]3 years ago
5 0

Answer:

1. 100%

2. 25%

3. 75%

Explanation:

Hope this helps, sorry in advance if any of these were wrong :)

You might be interested in
calculate the atomic mass of carbon if the two common isotopes of carbon have masses of 12.000 amu (98.89% abundance) and 13.003
Bingel [31]

12.01 amu

Work:

(12.000 × .9889) + (13.003 × .0111) = 12.01

  • turn the precents into decimals

6 0
3 years ago
Hcl and nh3 react to form a white solid, nh4cl. if cotton plugs saturated with aqueous solutions of each are placed at the ends
IgorLugansk [536]

24.4 cm.

<h3>Explanation</h3>

HCl and NH₃ reacts to form NH₄Cl immediately after coming into contact. Where NH₄Cl is found is the place the two gases ran into each other. To figure out where the two gases came into contact, you'll need to know how fast they move relative to each other.

The speed of a HCl or NH₃ molecule depends on its <em>kinetic energy</em>.

E_\text{k} = 1/2 \; m \cdot v^{2}

Where

  • E_\text{k} is the <em>kinetic energy</em> of the molecule,
  • m its mass, and
  • v^{2} the square of its speed.

Besides, the <em>kinetic theory</em> <em>of gases</em> suggests that for an ideal gas,

E_\text{k} \propto T

where \text{T} its temperature in degrees kelvins. The two quantities are directly proportional to each other. In other words, the <em>average kinetic energy</em> of molecules shall be the same for <em>any ideal gas </em>at the same<em> temperature</em>. So is the case for HCl and NH₃

E_\text{k} (\text{HCl}) = E_\text{k} (\text{NH}_3)

m(\text{HCl}) \cdot v^{2}(\text{HCl}) = E_\text{k} (\text{HCl}) = E_\text{k} (\text{NH}_3) = m(\text{NH}_3) \cdot v^{2}(\text{NH}_3)

Where

  • m(\text{HCl}), v(\text{HCl}), and E_\text{k}(\text{NH_3}) the mass, speed, and kinetic energy of an HCl molecule;
  • m(\text{NH}_3), v(\text{NH}_3), and E_\text{k}(\text{NH}_3) the mass, speed, and kinetic energy of a NH₃ molecule.

The ratio between the mass of an HCl molecule and a NH₃ molecule equals to the ratio between their <em>molar mass</em>. HCl has a molar mass of 35.45; NH₃ has a molar mass of 17.03. As a result, m(\text{HCl}) = 36.45 / 17.03 \; m(\text{NH}_3). Therefore:

36.45 /17.03\; m(\text{NH}_3) \cdot v^{2}(\text{HCl}) = m(\text{HCl}) \cdot v^{2}(\text{HCl}) = m(\text{NH}_3) \cdot v^{2}(\text{NH}_3)

36.45 /17.03\; v^{2}(\text{HCl}) = v^{2}(\text{NH}_3)

\sqrt{36.45 /17.03}\; v(\text{HCl}) = v(\text{NH}_3)

The <em>average </em>speed NH₃ molecules would be  \sqrt{36.45/17.03} \approx 1.463 <em>if</em>  the <em>average </em>speed of HCl molecules v(\text{HCl}) is 1.

\text{Time before the two gases meet} = \frac{\text{Length of the Tube}}{v(\text{HCl}) + v(\text{NH}_3)}

\text{Distance from the HCl end} = v(\text{HCl}) \times \text{Time before the two gases meet}\\\phantom{\text{Distance from the HCl end}} = v(\text{HCl}) \times \frac{ \text{Length of the Tube}}{v(\text{HCl}) + v(\text{NH}_3)}\\\phantom{\text{Distance from the HCl end}} = \frac{v(\text{HCl})}{v(\text{HCl}) + v(\text{NH}_3)} \times \text{Length of the Tube}\\\phantom{\text{Distance from the HCl end}} = \frac{1}{1 + 1.463} \times 60.0\; \text{cm} \\\phantom{\text{Distance from the HCl end}} = 24.4 \; \text{cm}

8 0
3 years ago
•6.5 L of a gas has a pressure of 840 mmHg and temperature of 84 0C. What will be its volume at STP
EastWind [94]

Answer:

5.5 L

Explanation:

Step 1: Given data

  • Initial volume (V₁): 6.5 L
  • Initial pressure (P₁): 840 mmHg
  • Initial temperature (T₁): 84 °C
  • Final volume (V₂): ?
  • Final pressure (P₂): 760 mmHg (standard pressure)
  • Final temperature (T₂): 273.15 K (standard temperature)

Step 2: Convert T₁ to Kelvin

We will use the following expression.

K = °C + 273.15

K = 84 °C + 273.15 = 357 K

Step 3: Calculate the final volume of the gas

We will use the combined gas law.

P₁ × V₁ / T₁ = P₂ × V₂ / T₂

V₂ = P₁ × V₁ × T₂ / T₁ × P₂

V₂ = 840 mmHg × 6.5 L × 273.15 K / 357 K × 760 mmHg = 5.5 L

5 0
3 years ago
How many atoms of hydrogen (h) are present in 200 molecules of ammonia (nh3)? express your answer numerically?
natita [175]
<span>Chemical formula of ammonia = NH3 As we can see there are three atoms of hydrogen in one molecule of ammonia. So in the 200 molecule of ammonia there will be = 200*3 = 600 atoms of hydrogen. Answer - 600 atoms of hydrogen.</span>
6 0
4 years ago
At what temperature does sulfur tetrafluoride have a density of 0.230 g/L at 0.0721 atm?
Allisa [31]

Explanation:

At 365 K temperature sulfur tetrafluoride have a density of 0.260 g/L at 0.0721 atm.

What is an ideal gas equation?

The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).

First, calculate the moles of the gas using the gas law,

PV=nRT, where n is the moles and R is the gas constant. Then divide

the given mass by the number of moles to get molar mass.

Given data:

P= 0.0721 atm

n=\frac{mass}{molar \;mass}n=

molarmass

mass

R= 0.082057338 \;L \;atm \;K^{-1}mol^{-1}R=0.082057338LatmK

−1

mol

−1

T=?

Putting value in the given equation:

\frac{PV}{RT}=n

RT

PV

=n

density = \frac{2 \;atm\; X molar\; mass}{0.082057338 \;L \;atm \;K^{-1}mol^{-1} X T}density=

0.082057338LatmK

−1

mol

−1

XT

2atmXmolarmass

0.260 g/L = \frac{0.0721 \;atm\; X 108.07 g/mol}{0.082057338 \;L \;atm \;K^{-1}mol^{-1} X T}0.260g/L=

0.082057338LatmK

−1

mol

−1

XT

0.0721atmX108.07g/mol

T = 365.2158727 K= 365 K

Hence , at 365 K temperature sulfur tetrafluoride have a density of 0.260 g/L at 0.0721 atm.

8 0
1 year ago
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