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3 years ago

If the period of a wave is 15 seconds, how many wavelengths pass a certain point in 2 minutes?

1 answer:

3 0

Hello
The period of a wave is the time it takes between two complete oscillations of the wave itself, i.e. it is the time that occurs between two consecutive wavelengths. Therefore, if we want to calculate how many wavelengths pass a certain point in $t=2~min=120~s$ , we need to divide the total time for the period of the wave, T:
$N= \frac{t}{T}= \frac{120~s}{15~s}=8$
So, the answer is 8 wavelengths.

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Care este legea conservarii sarcinii electrice? ma ajuta cineva?

Black_prince [1.1K]

Answer:

the law of conservation of electric charge that states that electric charge cannot be created or destroyed, it can only be exchanged between bodies.

Explanation:

In physics there are several conservation laws that are of great importance, among them we have the law of conservation of electric charge that states that electric charge cannot be created or destroyed, it can only be exchanged between bodies.

In general, the Earth is a very large body and is considered a reservoir where the electrical charge can be stored, but cannot be destroyed.

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3 years ago

A 25,000-kg train car moving at 2.50 m/s collides with and connects to a train car of equal mass moving in the same direction at

Margarita [4]

Answer:

14062.5 J

Explanation:

From the law of conservation of momentum,

Total momentum before collision = Total momentum after collision.

V = (m₁u₁ + m₂u₂)/(m₁+m₂).................1

Where V = common velocity after collision

Given: m₁ = m₂ = 25000 kg, u₁ = 2.5 m/s, u₂ = 1 m/s

Substitute into equation 1

V = [25000(2.5) + 25000(1)]/(25000+25000)

V = (62500+25000)/50000

V = 87500/50000

V = 1.75 m/s.

Note: The collision is an inelastic collision as such there is lost in kinetic energy of the system.

Total Kinetic energy before collision = kinetic energy of the first train car + kinetic energy of the second train car

E₁ = 1/2m₁u₁² + 1/2m₂u₂²........................ Equation 2

Where E₁ = Total kinetic energy of the body before collision, m₁ and m₂ = mass of the first train car and second train car respectively. u₁ and u₂ = initial velocity of the first train car and second train car respectively.

Given: m₁ = m₂ = 25000 kg, u₁ = 2.5 m/s, u₂ = 1 m/s

Substitute into equation 2

E₁ = 1/2(25000)(2.5)² + 1/2(25000)(1.0)²

E₁ = 12500(6.25) + 12500

E₁ = 78125+12500

E₁ = 90625 J.

Also

E₂ = 1/2V²(m₁+m₂)....................... Equation 3

Where E₂ = total kinetic energy of the system after collision, V = common velocity, m₁ and m₂ = mass of the first and second train car respectively.

Given: V = 1.75 m/s, m₁ = m₂ = 25000 kg

Substitute into equation 3

E₂ = 1/2(1.75)²(25000+25000)

E₂ = 1/2(3.0625)(50000)

E₂ = (3.0625)(25000)

E₂ = 76562.5 J.

Lost in kinetic Energy of the system = E₁ - E₂ = 90625 - 76562.5

Lost in kinetic energy of the system = 14062.5 J

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3 years ago

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4 years ago

When a cold air mass replaces a warm air mass, it's called a(n) _____ front?

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3 years ago

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One horsepower (1 hp) is the unit of power based on the work that a horse can do in one second. This is defined, in English unit

nikdorinn [45]

Power is defined as rate of work done which means it is work done in 1 second of time

Now it is given that we have a horse that will give power 745.7 W

So it will do work of 745.7 J in 1 second of time

now if we wish to find the work done by horse in 0.55 s

so we can say

$W = Power \times time$