All categories

4 years ago

What is the net charge of a copper atom if it gains 2 electrons?

1 answer:

7 0

If an atom gains electrons, it develops a negative charge equal to the number of electrons gained.
So the net charge on the copper atom which gained 2 electrons will be -2.

You might be interested in

It's important to match your exercise shoes with the type of exercise in which you will be participating, Please select the best

Feliz [49]

Answer:

true

Explanation:

8 0

4 years ago

Read 2 more answers

The bearing of a lighthouse from a ship was found to be N 37 degrees E. After the ship sailed 2.5 miles due south, the new beari

ella [17]

Answer:

The distance between the lighthouse and the ship

from the start position A = 5.08 miles

from the Final point B = 7.23 miles

Explanation:

Note: Refer the figure

Let the position of the lighthouse be 'L'

Given:

When the ship is at the position A, ∠DAL=37°

Now, when the ship sails through a distance of 2.5 i.e at position B

mathematically,

AB=2.5 miles

∠ABL=25°

Now,

∠DAL + ∠LAB = 180°

37° + ∠LAB = 180°

∠LAB = 180° - 37° = 143°

Also, In ΔLAB

∠LAB + ∠ABL + ∠ALB = 180°

143° + 25° + ∠ALB = 180°

∠ALB = 180° - 143° - 25° = 12°

Now using the concept of the sin law

In ΔLAB

$\frac{AL}{sin25^o}=\frac{2.5}{sin12^o}$

AL = 5.08 miles

and,

$\frac{BL}{sin143^o}=\frac{2.5}{sin12^o}$

BL = 7.23 miles

hence,

The distance between the lighthouse and the ship

from the start position A = 5.08 miles

from the Final point B = 7.23 miles

5 0

3 years ago

In the Daytona 500 auto race, a Ford Thunderbird and a Mercedes Benz are moving side by side down a straightaway at 71.5 m/s. Th

lisabon 2012 [21]

Answer:

957.4845 m

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

$v^2-u^2=2as\\\Rightarrow a=\frac{v^2-u^2}{2s}\\\Rightarrow a=\frac{0^2-71.5^2}{2\times 250}\\\Rightarrow a=-10.2245\ m/s^2$

$v=u+at\\\Rightarrow t=\frac{v-u}{a}\\\Rightarrow t=\frac{0-71.5}{-10.2245}\\\Rightarrow t=6.993\ s$

Time taken by the thunderbird to stop is 6.993 seconds

Time the thunderbird was at the pit is 5 seconds

$v^2-u^2=2as\\\Rightarrow a=\frac{v^2-u^2}{2s}\\\Rightarrow a=\frac{71.5^2-0^2}{2\times 350}\\\Rightarrow a=7.3\ m/s^2$

$v=u+at\\\Rightarrow t=\frac{v-u}{a}\\\Rightarrow t=\frac{71.5-0}{7.3}\\\Rightarrow t=9.79\ s$

Time taken to accelerate back to 71.5 m/s is 9.79 seconds

Total time to this point is 6.993+5+9.79 = 21.783 seconds

The Mercedes Benz is moving at a constant velocity hence it has no acceleration and we use the formula

Distance = Speed × Time

⇒Distance = 71.5 × 21.783 = 1557.4845 m

The thunderbird has covered 250+350 = 600 m

So, the distance between them is 1557.4845-600 = 957.4845 m

7 0

3 years ago

A proton moves with a speed of 0. 985c. (a) calculate its rest energy

mojhsa [17]

The rest energy of the proton will be 938 MeV. The rest energy is related to the rest mass of the proton.

<h3>What is rest energy?</h3>

The rest energy is the rest mass times the square of the speed of light of a particle at rest in an inertial frame of reference.

The rest energy is found as;

$\rm E_R= mC^2\\\\ E_R=(1.67 \times 10^{-27})\times 3 \times 10^8)^2\\\\ E_R= 9.375 \times 10^8 / eV$