I believe both C) and D) are correct, because both have enough electrons to show that the element has enough protons to be a transition metal, and both elements seem to have an electron configuration that exists in the ground state. We may need more information.
Answer:
Explanation:
You need to remember that the oxidation number of H is +1, except when it is in a metal hydrites like NaH, where its oxidation number is -1. Then, the oxidation number of O is -2, but in peroxides is -1. So with these rules you just have to multiply the ox. number with the name of atoms and all the elements in the reaction must sum 0.
Answer:
The mass of reactants and products for the reaction is this:
- 92 g Na, 32 g O₂, 124 g Na₂O
which is not a choice from the list.
Explanation:
4 moles of Na reacts with 1 mol of oxygen to produce 2 moles of sodium oxide.
Na = 23 g/m
4 moles are (4 . 23) = 92 g
O₂ = 32 g/m
It's a diatomic molecule (each O is 16 g/m)
Na₂O = 62 g/m
2 mol of sodium oxide will be (2 .62) = 124 grams
The mass of reactants and products for the reaction is this:
- 92 g Na, 32 g O₂, 124 g Na₂O
which is not a choice from the list.