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Irina18 [472]
3 years ago
5

How can wind put off fire?

Physics
2 answers:
kipiarov [429]3 years ago
7 0
♥ If the wind is strong enough it can do so.
♥ By having a strong enough wind you can blow out the fire before the flame can consume any more vapor.
♥ If the wind is fast enough, like a birthday cake candle for example, the wind will burn out.
ankoles [38]3 years ago
7 0
But wind also adds oxygen to the fire giving it a bigger flame right.
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Which causes the thermocline?
Igoryamba
<span>Thermocline is a layer between warm water from the ocean’s surface and cool water from below the ocean. In here, the temperature decreases rapidly from the warmer layer to the colder layer.  A thermocline forms due to the heat of the sun heating the ocean’s surface. Because of the difference in density between warm and cooler ocean water, cooler ocean water sinks and warmer ocean water floats. This is caused due to the heat and mass transfer between particles of the ocean. The answer is letter C. The sun’s radiation does not extend below a certain depth; therefore, deeper ocean water is colder than surface water.</span>
4 0
2 years ago
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Which object will have the most potential energy?
Svetradugi [14.3K]

Answer:  the most potential energy ==  5 kg book, 2 m from the ground= 98 Joules

Explanation:

potential energy = m g h

m = mass

g = acceleration due gravity  = 9.8 m/s²

h = distance above  ground

1.  Pe₁ = 1 kg x 2 m x g  = 2 g

2. Pe₂ = 5 kg x 2 m x g = 10 g = 10 kg m x 9,8 m/s² = 98 Joules

3. Pe₃ = 1 kg x 0,5 m x g = 0,5 g

4. Pe₄ = 5 kg x 0.5 m x g = 2,5 g  

10 > 2,5 > 2 >0,5

5 0
2 years ago
How does inertia affect a person who is not wearing a seatbelt during a collision?
ELEN [110]

A person who is not wearing a seatbelt during a collision will be thrown forward because it maintains forward motion

<h3>Further explanation </h3>

In Newton's law, it is stated that if the resultant force acting on an object of magnitude is zero,  it can be formulated :

\large{\boxed{\bold{\Sigma F = 0}}}

then the object tends to defend itself from its state. So for objects in a state of movement, objects tend to move forever. Likewise, for objects in a state of rest, they tend to remain forever. The tendency of objects like this is called<em> inertia </em>

The size of inertia is proportional to mass, the greater the mass of the object, the greater the inertia of the object.

In objects with mass m that move translatively, the object will maintain its linear velocity

When we are in a vehicle that moves forward, then we will still maintain a state of forwarding motion. If our vehicle stops suddenly, then we keep moving forward so we will be pushed forward. From this point, the use of a safety belt serves to hold back our movements so that there are no fatal accidents or collisions.

<h3>Learn more </h3>

Newton's law of inertia

brainly.com/question/1412777

example of Newton's First Law of inertia

brainly.com/question/1090504

law of motion

brainly.com/question/75210

Keywords: inertia, Newton's First Law

7 0
2 years ago
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Find the speed vfinal of the joined cars after the collision. mastering physics
Tanya [424]
<span>Px = 0 Py = 2mV second, Px = mVcosφ Py = –mVsinφ add the components Rx = mVcosφ Ry = 2mV – mVsinφ Magnitude of R = âš(Rx² + Ry²) = âš((mVcosφ)² + (2mV – mVsinφ)²) and speed is R/3m = (1/3m)âš((mVcosφ)² + (2mV – mVsinφ)²) simplifying Vf = (1/3m)âš((mVcosφ)² + (2mV – mVsinφ)²) Vf = (1/3)âš((Vcosφ)² + (2V – Vsinφ)²) Vf = (V/3)âš((cosφ)² + (2 – sinφ)²) Vf = (V/3)âš((cos²φ) + (4 – 2sinφ + sin²φ)) Vf = (V/3)âš(cos²φ) + (4 – 2sinφ + sin²φ)) using the identity sin²(Ď)+cos²(Ď) = 1 Vf = (V/3)âš1 + 4 – 2sinφ) Vf = (V/3)âš(5 – 2sinφ)</span>
6 0
3 years ago
A flux density of 1.2Wb/m^2 is required in the 1 mm air gap of an electromagnet having an iron path of length 1.5 m. Calculate t
Mandarinka [93]

Answer:

The mmf required is 1.125×10^{-3} A

Explanation:

The Magnetomotive force (mmf) is given by the formula below

F_{M} = Hl\\

where F_{M} is the Magnetomotive force (mmf)

H is the Magnetic field strength

l is the magnetic length

The magnetic permeability μ is given by

μ = B / H

Where B is the Magnetic flux density

and H is the Magnetic field strength

From the question,

B = 1.2Wb/m^2

μ = 1600m

From μ = B / H

∴H = B/μ

H = 1.2 / 1600\\

H = 7.5 × 10^{-4}A/m

Now, for the Magnetomotive force (mmf)

F_{M} = Hl\\

From the question

l = 1.5 m

∴ F_{M} = 7.5×10^{-4} × 1.5

F_{M} = 1.125×10^{-3} A

Hence, The mmf required is 1.125×10^{-3} A

3 0
3 years ago
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