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ivolga24 [154]
3 years ago
15

This type of energy can be transferred in three different ways: 1) direction contact through collisions (also called conduction)

, 2) through a fluid making a current created by less dense fluids floating and more dense fluids sinking (also called convection), and 3) by waves traveling with or without a medium (also called radiation)
this type of energy is often found in things like batteries or food


this is radiant energy from the sun; it's the only kind of energy we can see with our eyes


this has to do with the speed of an object and how much mass it has; basically how the object is moving


this is energy that is transferred by the movement of electrons through a conductor: the electrons create a current.


this can be either kinetic or potential and has to do with the energy of position and motion of an object


this is the energy found in the nucleus of an atom


this is the term used when energy changes from one form to another


this type of energy is stored energy; it can be increased by getting into a higher position and/or stretching an object such as a rubber band


this type of energy travels through vibrations on waves



1.
mechanical energy

2.
kinetic energy

3.
potential energy

4.
electrical energy

5.
light energy

6.
thermal energy

7.
sound energy

8.
chemical energy

9.
nuclear energy

10.
energy conversions
Physics
2 answers:
MA_775_DIABLO [31]3 years ago
4 0
I would say nuclear.
notka56 [123]3 years ago
3 0
<h2><u>Answer: </u></h2>

Energy is the ability of matter to produce work in the form of movement, light, heat, among others.

It should be noted that <u>energy is not created or destroyed, it is transformed</u>. This is a universal law, known as the Law of conservation of energy which  is also the first principle of Thermodynamics.

Taking this into account, let’s match each of the types of energy given in the questions with its respective definitions and meanings:

<h2>6.  Thermal energy </h2>

This type of energy can be transferred in three different ways: 1) direction contact through collisions (also called conduction), 2) through a fluid making a current created by less dense fluids floating and more dense fluids sinking (also called convection), and 3) by waves traveling with or without a medium (also called radiation)

<h2>8. Chemical energy </h2>

this type of energy is often found in things like batteries or food

<h2>5. light energy </h2>

this is radiant energy from the sun; it's the only kind of energy we can see with our eyes

<h2>2. kinetic energy </h2>

this has to do with the speed of an object and how much mass it has; basically how the object is moving

<h2>4. electrical energy </h2>

this is energy that is transferred by the movement of electrons through a conductor: the electrons create a current.

<h2>1. mechanical energy </h2>

this can be either kinetic or potential and has to do with the energy of position and motion of an object


<h2>9. nuclear energy </h2>

this is the energy found in the nucleus of an atom

<h2>10. energy conversions </h2>

this is the term used when energy changes from one form to another

<h2>3. potential energy </h2>

this type of energy is stored energy; it can be increased by getting into a higher position and/or stretching an object such as a rubber band

<h2>7. sound energy </h2>

this type of energy travels through vibrations on waves


You might be interested in
German physicist Werner Heisenberg related the uncertainty of an object's position (Δx) to the uncertainty in its velocity (Δ???
fredd [130]

Answer:

\Delta x = 5.47 \times 10^{-9} m

Explanation:

As we know by the principle of uncertainty that the product of uncertainty in position and uncertainty in momentum is given as

\Delta x \times \Delta P = \frac{h}{4\pi}

so here we know that

\Delta v = 0.01 \times 10^6 m/s

m = 9.11 \times 10^{-31} kg

so we have

\Delta x \times (9.11 \times 10^{-31})(0.01 \times 10^6) = \frac{6.26 \times 10^{-34}}{4\pi}

\Delta x = 5.47 \times 10^{-9} m

5 0
3 years ago
FIGURE 2 shows a 1.5 kg block is hung by a light string which is wound around a smooth pulley of radius 20 cm. The moment of ine
Sindrei [870]

Answer:

At t = 4.2 s

Angular velocity: 6. 17 rad /s

The number of revolutions: 2.06

Explanation:

First, we consider all the forces acting on the pulley.

There is only one force acting on the pulley, and that is due to the 1.5 kg mass attached to it.

Therefore, the torque on the pulley is

\tau=Fd=mg\cdot R

where m is the mass of the block, g is the acceleration due to gravity, and R is the radius of the pulley.

Now we also know that the torque is related to angular acceleration α by

\tau=I\alpha

therefore, equating this to the above equation gives

mg\cdot R=I\alpha

solving for alpha gives

\alpha=\frac{mgR}{I}

Now putting in m = 1.5 kg, g = 9.8 m/s^2, R = 20 cm = 0.20 m, and I = 2 kg m^2 gives

\alpha=\frac{1.5\cdot9.8\cdot0.20}{2}\boxed{\alpha=1.47s^{-2}}

Now that we have the value of the angular acceleration in hand, we can use the kinematics equations for the rotational motion to find the angular velocity and the number of revolutions at t = 4.2 s.

The first kinematic equation we use is

\theta=\theta_0+\omega_0t+\frac{1}{2}\alpha t^2

since the pulley starts from rest ω0 = 0 and theta = 0; therefore, we have

\theta=\frac{1}{2}\alpha t^2

Therefore, ar t = 4.2 s, the above gives

\theta=\frac{1}{2}(1.47)(4.2)^2

\boxed{\theta=12.97}

So how many revolutions is this?

To find out we just divide by 2 pi:

\#\text{rev}=\frac{\theta}{2\pi}=\frac{12.97}{2\pi}\boxed{\#\text{rev}=2.06}

Or about 2 revolutions.

Now to find the angular velocity at t = 4.2 s, we use another rotational kinematics equation:

\omega^2=w^2_0+2\alpha(\Delta\theta)_{}

Since the pulley starts from rest, ω0 = 0. The change in angle Δθ we calculated above is 12.97. The value of alpha we already know to be 1.47; therefore, the above becomes:

\omega^2=0+2(1.47)(12.97)w^2=38.12\boxed{\omega=6.17.}

Hence, the angular velocity at t = 4.2 w is 6. 17 rad / s

To summerise:

at t = 4.2 s

Angular velocity: 6. 17 rad /s

The number of revolutions: 2.06

3 0
1 year ago
What happens if you are riding your bike and hit something (like a curb) with the front wheel
evablogger [386]
You would flip forward or to the side
6 0
3 years ago
A microwave oven operating at 1.22 × 108 nm is used to heat 165 mL of water (roughly the volume of a teacup) from 23.0°C to 100.
ANTONII [103]

<u>Answer:</u> The number of photons are 3.7\times 10^8

<u>Explanation:</u>

We are given:

Wavelength of microwave = 1.22\times 10^8nm=0.122m    (Conversion factor:  1m=10^9nm  )

  • To calculate the energy of one photon, we use Planck's equation, which is:

E=\frac{hc}{\lambda}

where,

h = Planck's constant = 6.625\times 10^{-34}J.s

c = speed of light = 3\times 10^8m/s

\lambda = wavelength = 0.122 m

Putting values in above equation, we get:

E=\frac{6.625\times 10^{-34}J.s\times 3\times 10^8m/s}{0.122m}\\\\E=1.63\times 10^{-24}J

Now, calculating the energy of the photon with 88.3 % efficiency, we get:

E=1.63\times 10^{-24}\times \frac{88.3}{100}=1.44\times 10^{-24}J

  • To calculate the mass of water, we use the equation:

Density=\frac{Mass}{Volume}

Density of water = 1 g/mL

Volume of water = 165 mL

Putting values in above equation, we get:

1g/mL=\frac{\text{Mass of water}}{165mL}\\\\\text{Mass of water}=165g

  • To calculate the amount of energy of photons to raise the temperature from 23°C to 100°C, we use the equation:

q=mc\Delta T

where,

m = mass of water = 165 g

c = specific heat capacity of water = 4.184 J/g.°C

\Delta T = change in temperature = T_2-T_1=100^oC-23^oC=77^oC

Putting values in above equation, we get:

q=165g\times 4.184J/g.^oC\times 77^oC\\\\q=53157.72J

This energy is the amount of energy for 'n' number of photons.

  • To calculate the number of photons, we divide the total energy by energy of one photon, we get:

n=\frac{q}{E}

q = 53127.72 J

E = 1.44\times 10^{-24}J

Putting values in above equation, we get:

n=\frac{53157.72J}{1.44\times 10^{-24}J}=3.7\times 10^{28}

Hence, the number of photons are 3.7\times 10^8

4 0
3 years ago
Two stars have the same radius but have very different temperatures. the red star has a surface temperature of 3,000 k and the b
dangina [55]
I would say that insofar as the two stars temperatures are presumably closely related to their luminosity, that the blue star at 156,100 k compared to 3000k for the red star then the blue star has a luminosity of 52 times that of the red star.
4 0
3 years ago
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