Jumping on a trampoline is a classic example of conservation of energy, from potential into kinetic. It also shows Hooke's laws and the spring constant. Furthermore, it verifies and illustrates each of Newton's three laws of motion.
<u>Explanation</u>
When we jump on a trampoline, our body has kinetic energy that changes over time. Our kinetic energy is greatest, just before we hit the trampoline on the way down and when you leave the trampoline surface on the way up. Our kinetic energy is 0 when you reach the height of your jump and begin to descend and when are on the trampoline, about to propel upwards.
Potential energy changes along with kinetic energy. At any time, your total energy is equal to your potential energy plus your kinetic energy. As we go up, the kinetic energy converts into potential energy.
Hooke's law is another form of potential energy. Just as the trampoline is about to propel us up, your kinetic energy is 0 but your potential energy is maximized, even though we are at a minimum height. This is because our potential energy is related to the spring constant and Hooke's Law.
Answer: V = 15 m/s
Explanation:
As stationary speed gun emits a microwave beam at 2.10*10^10Hz. It reflects off a car and returns 1030 Hz higher. The observed frequency the car will be experiencing will be addition of the two frequency. That is,
F = 2.1 × 10^10 + 1030 = 2.100000103×10^10Hz
Using doppler effect formula
F = C/ ( C - V) × f
Where
F = observed frequency
f = source frequency
C = speed of light = 3×10^8
V = speed of the car
Substitute all the parameters into the formula
2.100000103×10^10 = 3×10^8/(3×10^8 -V) × 2.1×10^10
2.100000103×10^10/2.1×10^10 = 3×108/(3×10^8 - V)
1.000000049 = 3×10^8/(3×10^8 - V)
Cross multiply
300000014.7 - 1.000000049V = 3×10^8
Collect the like terms
1.000000049V = 14.71429
Make V the subject of formula
V = 14.71429/1.000000049
V = 14.7 m/s
The speed of the car is 15 m/s approximately
Answer:
The vibrational frequency of the rope is 5 Hz.
Explanation:
Given;
number of complete oscillation of the rope, n = 20
time taken to make the oscillations, t = 4.00 s
The vibrational frequency of the rope is calculated as follows;
Therefore, the vibrational frequency of the rope is 5 Hz.
Answer:
1. 10.5 Kg
2. s/g
Explanation:
1. Determination of the mass of gasoline
Density of gasoline = 0.7 Kg/L
Volume of gasoline = 15 L
Mass of gasoline =?
The density of a substance is simply defined as the mass of the substance per unit volume of the substance. Mathematically, the density of a substance can be expressed as:
Density = mass / volume
With the above formula, we can obtain the mass of the gasoline as follow:
Density of gasoline = 0.7 Kg/L
Volume of gasoline = 15 L
Mass of gasoline =?
Density = mass / volume
0.7 = Mass of gasoline / 15
Cross multiply
Mass of gasoline = 0.7 × 15
Mass of gasoline = 10.5 Kg
2. Density has various units some are listed below:
I. Kilogram per litre (Kg/L)
II. Kilogram per cubic metre (Kg/m³)
III. Milligram per millilitre (mg/mL)
IV. Gram per millilitre (g/mL)
V. Gram per cubic centimetre (g/cm³)
Considering the options given in the question above, it is evident that second per gram (s/g) is not a unit of density because density is mass per unit volume.
Symbols such as cross motivates me to go to church.
