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san4es73 [151]
3 years ago
6

Astronauts aboard the U.S.S. Burger decide to fire the rocket thrusters for 3.0 seconds to make a course correction. While the t

hrusters are on, the ship moves a total distance of 10,500 kilometers and increases its speed by 340 meters / sec. What is the U.S.S. Burger’s Δ V, (where V stands for speed) in meters / second?
Physics
1 answer:
Cloud [144]3 years ago
8 0

Answer:

340 m/s

Solution:

As per the question;

Time, t = 3.0 s

Total distance moved by the ship, d = 10,500 km

The increase in speed, v = 340 m/s

Now,

To calculate the U.S.S Burger's change in speed, \Delta V:

The final velocity is given by:

v_{f} = 340 + v_{i}                      (1)

where

v_{f} = final\ velocity

v_{i} = initial\ velocity

Also, the change in velocity is given by:

\Delta v = v_{f} - v_{i}                    (2)

Now, from eqn (1) and (2):

\Delta = 340 + v_{i} - v_{i} = 340\ m/s

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Answer:

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The speed is defined as the rate of change of distance.

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When we know the distance and the time, we get the value of speed. So, e know that who is moving fast or slow.

hen a graph is pltted beteen the distance and time, the slope of the graph gives the value of speed. So, by checking the slopes, hoseslope ismore, the speed is more and thusit is moving faster.

So, i agree with the statement.  

6 0
2 years ago
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