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DiKsa [7]
3 years ago
5

Calculate the wavelength λ1 for gamma rays of frequency f1 = 7.20×1021 hz .

Physics
1 answer:
bagirrra123 [75]3 years ago
5 0
The relationship between wavelength \lambda, frequency f and speed of light c for an electromagnetic wave is
\lambda= \frac{c}{f}
Using the data of the problem, we find
\lambda= \frac{3\cdot 10^8 m/s }{7.20 \cdot 10^{21} Hz}=4.17 \cdot 10^{-14} m
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I WIIL GIVE BRAINLIEST
Evgesh-ka [11]

Answer:

Genetic engineering because the genes of the plants were modified.

Explanation:

We can eliminate the second and fourth ones right off of the bat because artificial selection is breeding organisms until they display a trait or a series of traits that is desired, but in this situation, the scientist directly altered the DNA. Genetic engineering, just like all other technologies, aren't necessarily helpful to society all of the time; they always have their draw backs. The answer has to be the third one because the DNA is directly altered, just like the answer choice says.

4 0
3 years ago
A stone is dropped into a lake, creating a circular ripple that travels outward at a speed of 50 cm/s. Find the rate at which th
Drupady [299]
The radius of the circle, in cm, after t seconds would be 50t 
The area, A, of the circle after t seconds is expressed in the equation: A = pi * r^2 
A = pi * (50T)^2 = pi*2500*t^2 
The change of area per unit time is obtained by differentiating the equation
A' = pi*2500*2*t A' = pi*5000*t
when t = 3 secondsA' = pi*5000*3 = 47122 cm2/s
6 0
3 years ago
The strength of the electric field 0.5 m from a 6 uC charge is
Triss [41]

Answer:

E= 2.158× 10*5N/C

Explanation:

K= 8.99×10*9, q= 6×10*-6C, d= 0.5m

E= kq/d*2

E= (8.99×10*9× 6×10*-6)/0.5*2

E= 215760

E= 2.158 ×10*5N/C

5 0
3 years ago
A 3,220 lb car enters an S-curve at A with a speed of 60 mi/hr with brakes applied to reduce the speed to 45 mi/hr at a uniform
Grace [21]

The magnitude of the total friction force exerted by the road on the tires at B will be 919.46 lb.

<h3>What is the friction force?</h3>

It is a type of opposition force acting on the surface of the body that tries to oppose the motion of the body. Its unit is Newton (N).

Mathematically, it is defined as the product of the coefficient of friction and normal reaction.

The given data in the problem is;

The weight is,W= 3,220 lb

The speed is,u= 60 mi/hr

The reducing speed is,v= 45 mi/hr

The distance traveled is,d= 300 ft

The radius of curvature of the path of the car at B is,R= 600 ft.

1 mile = 5280 ft

From the Newtons' equation of motion;

\rm v^2 = u^2 +2ad \\\\ \rm (45 \times \frac{5280}{3600} )^2 = (60 \times  \frac{5280}{3600}  )^2 +2a\times 300 \\\\

The tangential accelerations are;

\rm a_t = \frac{66^2 -88^2}{600} \\\\ \rm a_t =  -5.65 ft/sec^2 \\\\

The force is found as;

\rm \sum F = ma \\\\ \frac{3220}{32.2} \times -5.65 \\\\ F_T= 565 \ lb

The normal force  is;

\rm F_n = \frac{3220}{32.2} \times \frac{66^2}{600} \\\\ F_N =726 \ lb

The net or the total friction force exerted by the road on the tires at B. is found as;

\rm F = \sqrt{(565)^2+(726)^2} \\\ F = 919.946 \ lb

Hence, the magnitude of the total friction force exerted by the road on the tires at B will be 919.46 lb.

To learn more about the friction force, refer to the link;

brainly.com/question/1714663

#SPJ1

6 0
2 years ago
Jonah observes the Sun through a special filtered telescope during a total solar eclipse. He sees a red ring and a faint white r
ivann1987 [24]

The answer would be C. chromosphere and corona.

8 0
3 years ago
Read 2 more answers
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