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The volume is 12 mL (0.012 L)
Before the aluminum was added, the water reached 132mL. After it was added, it reached 144. That means the Aluminum takes up (144-132)= 12mL of space.
The density = mass/volume. If the aluminum bar has a mass of 78g and volume of 0.012L, 78/0.012=6,500 g/L
Group 17
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Let the total mass of compound is 100g
The mass of each element will be
Al = 22.10 g
P = 25.40 g
O = 52.50 g
In order to determine the molecular formula we will calculate the molar ratio of the given elements
Atomic weight of Al : 27 g/ mol
Atomic weight of P : 3 1g /mol
Atomic weight of O : 16 g /mol
Moles of Al = mass / atomic mass = 22.10 / 27 = 0.819
Moles of P = mass / atomic mass = 25.40/ 31 = 0.819
Moles of O = mass / atomic mass = 52.50/ 16 = 3.28
Now we will divide the moles of each element with the lowest moles obtained to obtain a whole number ratio of moles of each element present
moles of Al = 0.819 / 0.819 = 1
moles of P = 0.819 / 0.819 = 1
moles of O = 3.28 / 0.819 = 4
So the empirical formula will be : AlPO4
Between equatorial positions, the F-P-F angle is 120°, and between axial and equatorial positions, it is 90°.
<h3>What in chemical bonding is equatorial position?</h3>
Equatorial Organic Chemistry Illustrated Glossary. Equatorial: In cyclohexane, a bond that runs parallel to the ring's axis (i.e., it follows the chair's equator), or a group joined by such a bond. Positions A are axial, and positions E are equatorial.
<h3>Why do equatorial positions have greater stability?</h3>
As was said in the preceding section, the equilibrium favors the more stable conformer because the chair conformation, in which the methyl group is equatorial, lowers steric repulsion. All monosubstituted cyclohexanes share this property.
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