Need help answering these questions. Please show all work. Thank you so much.

Fill the three 3d subshells with the specified number of electrons.

lana66690 [7]

1. 5 electrons.

$3d^{5}$

Therefore, the 3d subshells blanks will be like this:
↑ ↑ ↑ ↑ ↑

2. 6 electrons.

$3d^{6}$

The 3d subshells blanks will be:
↑↓ ↑ ↑ ↑ ↑

3. 7 electrons.

$3d^{7}$

The 3d subshells blanks will be:
↑↓ ↑↓ ↑ ↑ ↑

Hope you could understand.

If you have any query, feel free to ask.

8 0

2 years ago

What is the V2O5 coefficient??

AnnyKZ [126]

Answer:

1235

Explanation:

if thers a a guess in that number

6 0

3 years ago

Calculate the mass of magnesium carbonate ( MgCO3), in grams, required to produce 110.0 g of carbon dioxide using the following

bearhunter [10]

Answer:

$210.7~g~MgCO_3$

Explanation:

We have to start with the reaction:

$MgCO_3~->~MgO~+~CO_2$

We have the same amount of atoms on both sides, so, we can continue. The next step is to find the number of moles that we have in the 110.0 g of carbon dioxide, to this, we have to know the atomic mass of each atom:

C: 12 g/mol

O: 16 g/mol

Mg: 23.3 g/mol

If we take into account the number of atoms in the formula, we can calculate the molar mass of carbon dioxide:

$(12*1)+(16*2)=44~g/mol$

In other words: $1~mol~CO_2=~44~g~CO_2$ . With this in mind, we can calculate the moles:

$110~g~CO_2\frac{1~mol~CO_2}{44~g~CO_2}=25~mol~CO_2$

Now, the molar ratio between carbon dioxide and magnesium carbonate is 1:1, so:

$2.5~mol~CO_2=2.5~mol~MgCO_3$

With the molar mass of $MgCO_3$ ( $(23.3*1)+(12*1)+(16*3)=84.3~g/mol$ . With this in mind, we can calculate the grams of magnesium carbonate:

$2.5~mol~MgCO_3\frac{84.3~g~MgCO_3}{1~mol~MgCO_3}=210.7~g~MgCO_3$

I hope it helps!

8 0

3 years ago

The term “periodic” helps identify _______ that occur in the table, like electronegativity or atomic radii.

stepan [7]

Answer: ITS C OR B I THINK BUT I HAVE A FEELING ITS ONE OF THOSE

Explanation:

IM SO SORRY IF ITS WRONG KSDBDZDH

8 0

3 years ago

Read 2 more answers

Will bromine react with sodium and why?

Archy [21]

When you write down the electronic configuration of bromine and sodium, you get this

Na:
Br:

So here we the know the valence electrons for each;

Na: (2e)
Br: (7e, you don't count for the d orbitals)

Then, once you know this, you can deduce how many bonds each can do and you discover that bromine can do one bond since he has one electron missing in his p orbital, but that weirdly, since the s orbital of sodium is full and thus, should not make any bond.

However, it is possible for sodium to come in an excited state in wich he will have sent one of its electrons on an higher shell to have this valence configuration:

where here now it has two lonely valence electrons, one on the s and the other on the p, so that it can do a total of two bonds.That's why bromine and sodium can form

4 0

3 years ago