Answer:
0.65 m/s
Explanation:
Applying the equation,
v = u + at
35 = u + a×2.3 -(1)
Again, applying the equation,
s = ut +
a
41 = u×2.3 +
× 
35.65 = 2u + 2.3a -(2)
comparing first and second we get u= 0.65 m/s
Save money on fuel and go for longer
Answer:
5069.04 seconds
Explanation:
The parameter we are looking for is called the Orbital period of the Hubble Space Telescope.
It is given as:

where r = radius of orbit of Hubble Space Telescope
G = gravitational constant = 
M = Mass of earth
We are given that:
r = radius of the earth + distance of HST from earth
r = 
M = 
Therefore, T will be:


The orbital period of the Hubble Space Telescope is 5069.04 seconds.
Answer:
The magnitude of the torque the bucket produces around the center of the cylinder is 26.46 N-m.
Explanation:
Given that,
Mass of bucket = 54 kg
Radius = 0.050 m
We need to calculate the magnitude of the torque the bucket produces around the center of the cylinder
Using formula of torque


Where, m = mass
g = acceleration due to gravity
r = radius
Put the value into the formula


Hence, The magnitude of the torque the bucket produces around the center of the cylinder is 26.46 N-m.
Kinetic Energy is defined by Ke=1/2mv^2. Plug in and solve for v.
2,000 = 1/2(1000)(v)^2
4=(v)^2
v=2 m/s
The car must move at 2 m/s to have a Ke of 2,000 Joules.