Answer:
0.65 m/s
Explanation:
Applying the equation,
v = u + at
35 = u + a×2.3 -(1)
Again, applying the equation,
s = ut + a
41 = u×2.3 + ×
35.65 = 2u + 2.3a -(2)
comparing first and second we get u= 0.65 m/s
Who first studied the relationship between buoyant force and the weight of a displaced fluid?
1 answer:
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Answer:
5069.04 seconds
Explanation:
The parameter we are looking for is called the Orbital period of the Hubble Space Telescope.
It is given as:
where r = radius of orbit of Hubble Space Telescope
G = gravitational constant =
M = Mass of earth
We are given that:
r = radius of the earth + distance of HST from earth
r =
M =
Therefore, T will be:
The orbital period of the Hubble Space Telescope is 5069.04 seconds.
Answer:
The magnitude of the torque the bucket produces around the center of the cylinder is 26.46 N-m.
Explanation:
Given that,
Mass of bucket = 54 kg
Radius = 0.050 m
We need to calculate the magnitude of the torque the bucket produces around the center of the cylinder
Using formula of torque
Where, m = mass
g = acceleration due to gravity
r = radius
Put the value into the formula
Hence, The magnitude of the torque the bucket produces around the center of the cylinder is 26.46 N-m.